The equation of the line is y = -x + 6 if the passes through the point (4, 2).
<h3>What is a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:

The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
It is given that:
From the graph:
The slope of the line g = (0-5)/(-5-0)
= 1
The slope perpendicular to the line g:
= -1
y - 2 = -(x - 4)
y - 2 = -x + 4
y = -x + 6
Thus, the equation of the line is y = -x + 6 if the passes through the point (4, 2).
Learn more about the straight line here:
brainly.com/question/3493733
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Answer: A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.
Step-by-step explanation:
I just got it right on PLATO, so I know it’s 100% correct.
Answer:
y = 2x
the formula for linear equations are y = mx+c,
where m is the gradient,
and c is the y-intercept
to find m (the gradient):
1. pick to points on the graph (eg. -2,-4 and 2,4)
2 substitute the values into the formula for gradient y2-y1/x2-x1.
m = y2-y1/x1-x2
= -4 -4/-2-2
= -8/-4
= 2
to find c (y-intercept):
- the y-intercept is where the graph cuts the y axis
- in this graph, the y-intercept is 0
hence,
c = 0
substitute m = 2 and c = 0 to y = mx+c,
y = 2x + 0
y = 2x
hence, the equation that best represents the relationship shown in the graph is y = 2x.
Hello,

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