The Pyth. Thm. applies here:
(√x + 1)^2 + (2√x)^2 = (2√x + 1 )^2
Expanding the squares:
x + 2sqrt(x) + 1 + 4x = 4x + 4sqrt(x) + 1
Let's subtract x + 2sqrt(x) + 1 + 4x from both sides:
4x + 4sqrt(x) + 1
-(x + 2sqrt(x) + 1 + 4x)
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3x + 2sqrt(x) - 4x = 0
Then 2sqrt(x) = x
Squaring both sides, 4x = x^2, or x^2 - 4x = 0. Then (x-4)x = 0, and the two possible solutions are 0 and 4.
Check these results by substitution. Does the Pyth. Thm. hold true for x=4?
Probablity is (desired outcomes)/(total possible outcomes)
total possible outcomes is 50
find the desired oucomes
les than 10
those ar
1,2,3,4,5,6,7,8,9
9 numbers less than 10
OR
multipule of 12
12,24,36,48
4 of them
9+4=13
13=total possible
13/50
C
Answer:
6.61=6.610
Step-by-step explanation:
6.61=6.610
After point we can increase no. Of zero.
Answer:
If the line is horizontal, then all that have a 2 in the Y space will apply because the line goes across meaning that it won't change on the vertical axis.
(5,2) and (-2, 2)
4.2 would be an example, but there are many more. Honestly, it wouldn't matter as long as it was less than 6.73.
