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guapka [62]
2 years ago
12

25 points help please just give the y intercept and slope

Mathematics
1 answer:
ycow [4]2 years ago
7 0

Answer:

eq 1 yint = 7

eq2 yint= 4

slope for both is 1

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BRAINIEST AND 10 POINTS
SpyIntel [72]

Answer:

16

Step-by-step explanation:

just use a calculator

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3 years ago
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Rewrite the expression. Use and exponent, rather than repeated multiplication (-4)(-4)
IrinaK [193]

-4²

Any number repeatedly multiplied by itself has an exponent. so (-4)(-4) has an exponent of 2 while (-4)(-4)(-4) would have an exponent of 3 and be written as -4³.

Also extra tip: Negative numbers multiplied by a negative number will always be positive.

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4 years ago
Asap answer pls-----------
marissa [1.9K]

Answer:

y=\frac{4}{5}x-\frac{18}{5}

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0).

<u>1) Determine the slope (m)</u>

m=\frac{y_2-y_1}{x_2-x_1} where two points on the line are (x_1,y_1) and (x_2,y_2)

In the graph, the points (-3,-6) and (2,-2) are plotted clearly, so we can use these to help us find the slope. Plug them into the equation:

m=\frac{-6-(-2)}{-3-2}\\m=\frac{-6+2}{-3-2}\\m=\frac{-4}{-5}\\m=\frac{4}{5}

Therefore, the slope of the line is \frac{4}{5}. Plug this into y=mx+b :

y=\frac{4}{5}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{4}{5}x+b

Typically, given a graph, we could look at where exactly the line crosses the y-axis to determine b. However, because it appears ambiguous on this graph, we must solve it algebraically.

Plug in one of the given points (2,-2) and solve for b:

-2=\frac{4}{5}(2)+b\\-2=\frac{8}{5}+b

Subtract \frac{8}{5} from both sides to isolate b

-2-\frac{8}{5}=\frac{8}{5}+b-\frac{8}{5}\\-\frac{18}{5} =b

Therefore, the y-intercept of the line is -\frac{18}{5}. Plug this back into y=\frac{4}{5}x+b:

y=\frac{4}{5}x+(-\frac{18}{5})\\y=\frac{4}{5}x-\frac{18}{5}

I hope this helps!

8 0
3 years ago
Which statements are true regarding undefinable terms in geometry? Check all that apply. A point’s location on the coordinate pl
hodyreva [135]
The correct statements are as follows:

A point's location on the coordinate plane is indicated by an ordered pair, (x,y). 

// Hope this helped, comment below for further clarification //
4 0
4 years ago
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Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable
bekas [8.4K]

Answer:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

u=\frac{y}{x}

Multiply both sides by x:

ux=y

Second step: Differentiate the substitution:

u'x+u=y'

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}

u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of x^2 so I'm going to divide top and bottom by x^2:

u'x+u=\frac{u+u^2}{3+u^2}

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

u'x=\frac{u+u^2}{3+u^2}-u

Find a common denominator: Multiply second term on right hand side by \frac{3+u^2}{3+u^2}:

u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}

Combine fractions while also distributing u to terms in ( ):

u'x=\frac{u+u^2-3u-u^3}{3+u^2}

u'x=\frac{-u^3+u^2-2u}{3+u^2}

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

u' \frac{3+u^2}{-u^3+u^2-2u}x=1

Divide both sides by x:

\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}

Reorder the top a little of left hand side using the commutative property for addition:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0
3 years ago
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