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3 years ago

First ten nonzero multiples of 10

Mathematics

1 answer:

Ray Of Light [21]3 years ago

8 0

10, 20, 30, 40, 50, 60, 70, 80, 90, 100

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2. Evaluate f(x) = 3x+5/x-1<br> at x = 3

pashok25 [27]

Answer

Let f(x) = ax + b

Then

f(x + 1) = a(x + 1) + b

= ax + a + b

Hence, a = 3, and a + b = 5, b = 2

f(-2) = 3(-2) + 2

= -6 + 2

= - 4

f(2x) = 3(2x ) + 2

= 6x + 2

6 0

3 years ago

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago

Help me out Wishing. What are the trigonometric ratios. Write all six.

MAVERICK [17]

Answer:

Sine - opposite : hypotenuse

Cosine - adjacent : hypotenuse

Tangent - opposite : adjacent

Cosecant - hypotenuse : opposite

Secant - hypotenuse : adjacent

Cotangent - adjacent : opposite

3 0

3 years ago

Read 2 more answers

Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths

kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment

Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13