Answer is
Choice C
I used the power rule for integrals.
A. x + 5
According to the table, the function is shifted up 5 units.
Answer:
(x-2), (x+2), (3x-5)
Step-by-step explanation:
Factors of 3: ±1, ±3
Factors of 20: ±1, ±2, ±4, ±5, ±10, ±20
Possible factors of the polynomial: ±1, ±2, ±3, ±4, ±5, ±10, ±20, .... (there's a lot more but you probably do not need to list them all)
Pick a number to divide the polynomial by (I picked 2)
(3x³-5x²-12x+20)÷(x-2) = 3x²+x-10
So (x-2) is a factor of f(x) = 3x³-5x²-12x+20
Factor 3x²+x-10 = (3x-5)(x-2) these are the other factors of f(x) = 3x³-5x²-12x+20
Answer:
Natalie bought 500 apples at $0.40 each, then she pays $0.40 500 times, this means that the total cost of the 500 apples is:
Cost = 500*$0.40 = $200
Now she threw away n apples from the 500 apples, then the number of apples that she has now is:
apples = 500 - n
And she sells the remaining apples for $0.70 each.
a) The amount that she gets by selling the apples is:
Revenue = (500 - n)*$0.70
b) We know that she did not make a loss, then the revenue must be larger than the cost, this means that:
cost ≤ revenue
$200 ≤ (500 - n)*$0.70
c) We need to solve the inequality for n.
$200 ≤ (500 - n)*$0.70
$200/$0.70 ≤ (500 - n)
285.7 ≤ 500 - n
n + 285.7 ≤ 500
n ≤ 500 - 285.7
n ≤ 214.3
Then the maximum value of n must be equal or smaller than 214.3
And n is a whole number, then we can conclude that the maximum number of rotten apples can be 214.
The best way to solve this one would be simple cross multiplying. Multiply the top of one side with the bottom of the other side. In this problem you need to multiply X with 8 and multiply 3 with 5. You'll get an equation of 8X=15, then divide both sides by 8 so that you get X by itself. Your answer will them be X=1.875