Question

3\sqrt{2} - 2\sqrt{18} + 6\sqrt{8}[/tex]

Answer 1

Answer:

$\sf \bold 9\sqrt{2}$

Step-by-step explanation:

Simplifying radicals

    Step1: Prime fatorize and reduce to simplest form

    Step2:  Combine like radicals

    $\sf 3\sqrt{2} - 2\sqrt{18}+6\sqrt{8}= 3\sqrt{2}- 2\sqrt{3*3*2}+6\sqrt{2*2*2}$

                                    $\sf = 3\sqrt{2}-2*3\sqrt{2} +6*2\sqrt{2}\\\\=3\sqrt{2}-6\sqrt{2}+12\sqrt{2}\\\\=(3-6+12)\sqrt{2}\\\\ = 9\sqrt{2}$