![\left ( \frac{3}{2}\times \frac{4}{5} \right )+\left ( \frac{9}{5}- \frac{10}{3} \right )-\left ( \frac{1}{2}\times \frac{3}{4} \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B3%7D%7B2%7D%5Ctimes%20%5Cfrac%7B4%7D%7B5%7D%20%5Cright%20%29%2B%5Cleft%20%28%20%5Cfrac%7B9%7D%7B5%7D-%20%5Cfrac%7B10%7D%7B3%7D%20%5Cright%20%29-%5Cleft%20%28%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5Cfrac%7B3%7D%7B4%7D%20%5Cright%20%29%20)
In the first parenthesis, multiply the numerators so we get -12 and after multiply the denominator we will get 10
So the fraction in the first parenthesis will be ![\left ( \frac{-12}{10} \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B-12%7D%7B10%7D%20%5Cright%20%29%20)
To solve the 2nd parenethesis, find the LCD of the denominator.
So the LCD of 5 and 3 = 15,
Now make the each denominator same as that of LCD.
So the new fractions in the 2nd parenthesis =
= ![\left ( \frac{-23}{15} \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B-23%7D%7B15%7D%20%5Cright%20%29%20)
In the third parenthesis, multiply the numerators so we get 3 and after multiply the denominator we will get 8
So third parenthesis = ![\left ( \frac{3}{8}\ \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B3%7D%7B8%7D%5C%20%5Cright%20%29%20)
= ![\left ( \frac{-12}{10} \right ) + \left ( \frac{-23}{15} \right ) -\left ( \frac{3}{8}\ \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B-12%7D%7B10%7D%20%5Cright%20%29%20%2B%20%5Cleft%20%28%20%5Cfrac%7B-23%7D%7B15%7D%20%5Cright%20%29%20-%5Cleft%20%28%20%5Cfrac%7B3%7D%7B8%7D%5C%20%5Cright%20%29%20%20)
LCD of 12,15 and 8 is 120
=![\left ( \frac{-144}{120} \right ) + \left ( \frac{-184}{120} \right ) -\left ( \frac{45}{120}\ \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B-144%7D%7B120%7D%20%5Cright%20%29%20%2B%20%5Cleft%20%28%20%5Cfrac%7B-184%7D%7B120%7D%20%5Cright%20%29%20-%5Cleft%20%28%20%5Cfrac%7B45%7D%7B120%7D%5C%20%5Cright%20%29%20)
=![\left ( \frac{-373}{120} \right )](https://tex.z-dn.net/?f=%20%5Cleft%20%28%20%5Cfrac%7B-373%7D%7B120%7D%20%5Cright%20%29%20)
Answer:
Step-by-step explanation:
Given that,
The surface Area of a cube is equal to the sum of the 6 Square faces
And each side has a length of 's'
Formula to calculate the surface area is
A = 6s²
Given that the surface area is 1944 units²
It is a straight forward question,
The questions already gave us the formula for area of a cube and which is 6s² and the question said that if the area is 1944 unit², find 's'
So,
A = 1944
6s² = 1944
s² = 1944 / 6
s² = 324
s = √324
s = 18 units
So, the value of s- is 18 units
Graph the equations and locate the intersection.
(-3,6)
Answer:
100
Step-by-step explanation:
200+3qq+400+q3q
200+3q²+400+3q²
3q²-3q²+400-200
q²=200
q²=200/2
q²=100