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masya89 [10]
3 years ago
12

A company has budgeted $21,200 to buy TV ads. A TV ad costs $6,575 per

Mathematics
1 answer:
amm18123 years ago
3 0

Answer:

about 300

21200 rounded is 21000 and 6575 rounded is 7000

Step-by-step explanation:

21000÷7000=300

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3 years ago
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Find the volume of this cylinder.
Lina20 [59]

Answer:

The answer is 3418.1 ft rounded to the nearest tenth.

Step-by-step explanation:

The total volume of the cylinder can be defined by the Area of circular base * Perpendicular height.

The area of the circular base can be calculated as

\pi \times  {r}^{2}

where r is the radius of the circular base, which is 8 ft.

The area of the circular base is

\pi \times  {8}^{2}  = 64\pi

We also know the height of the cylinder is 17 ft.

Hence, the volume of the cylinder is

64\pi \times 17 = 1088\pi = 3418.0528...

This will be rounded up to 3418.1 with the nearest tenth

8 0
3 years ago
britney is buying a hat at the mall. the shirt costs $31.59, and the hat costs $19.46. if Britney gives the sales clerk $100.00,
kiruha [24]

Answer: 48.95

Step-by-step explanation:

so first I would add together the cost of the shirt and hat

31.59 +19.46 = 51. 05

then I would take away the 51.05 ( the total ) from $100

100 - 51.05 = $48.95

So she would get $48.95 for change

7 0
3 years ago
Use substitution to solve the system of equations.
kakasveta [241]

Answer:

C (let me know if I am wrong!)

Step-by-step explanation:

We need to solve the equation.

If 5x+y = -24, then -24 - 5x = y.

x+ 3(-24-5x) = -2

= -14x-72=-2

= -14x-72+72=-2+72

= -14x=70

= -5

If x = -5, then -5 + 3y = -2.

3y = -2+5

3y = 3

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So the answer is C.

4 0
3 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
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