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aleksklad [387]
2 years ago
14

PLEASE HELP ME PLEASE

Mathematics
2 answers:
stepan [7]2 years ago
8 0

Answer:

I think true because that's the only star that is closest to the earth

Assoli18 [71]2 years ago
4 0

Answer

true

Step-by-step explanation:

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5 markers cost $6.55.Which equation would help determine the cost of 4 markers?
Semmy [17]

5 markers -------> $6.55

4 markers -------> x

undefined

4 0
1 year ago
A table costs Rs 720 to make. He sells it for Rs 920. What percentage of profit did he earn?
jenyasd209 [6]

Answer:

27 7/9%

Step-by-step explanation:

Take the selling price and subtract the cost

920 -720 = 200

Divide it by the cost

200/720

.27777777

Change to percent form

27.777777%

27 7/9%

3 0
3 years ago
Read 2 more answers
In the graph shown, which ordered pair does NOT represent a solution to the graph?
andreyandreev [35.5K]
A) (1, 7) Doesn't
B) (0, 4) Doesn't
C) (2, –2) Doesn't
D) (3, –5) DOES

All the steps are right at the exception of line 7 (and onwards)

line 6 : 6x = 42 (it's right). Now divide both sides by 6:

line 7 should be:  6x/6 = 42/6
line 8 should be: x = 7. 

8 0
3 years ago
Read 2 more answers
7 in 10 auto accidents involve a single vehicle. Suppose 14 accidents are randomly selected. (Round your answers to five decimal
Tpy6a [65]

Answer:

Step-by-step explanation:

Assuming a binomial distribution for the number of auto accidents. If 7 in 10 auto accidents involve a single vehicle, the probability, p = 7/10 = 0.7

Then the probability that the accident involved multiple vehicles is

q = 1 - p = 1 - 7/10 = 3/10 = 0.3

Since 14 accidents are randomly selected, n = 14

The formula for binomial distribution is expressed as

P(x = r) = nCr × q^(n - r) × p^r

a) we want to determine P(x = 4) =

P(x = 4) = 14C4 × 0.3^(14 - 4) × 0.7^4

P(x = 4) = 0.00142

b) we want to find P(x lesser than or equal to 4) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P( x = 4)

P(x = 0) = 14C0 × 0.3^(14 - 0) × 0.7^0 = 0.00000004783

P(x = 1) = 14C1 × 0.3^(14 - 1) × 0.7^1 = 0.00011

P(x = 2) = 14C2 × 0.3^(14 - 2) × 0.7^2 = 0.00002

P(x = 3) = 14C3 × 0.3^(14 - 3) × 0.7^3 = 0.00022

P(x = 4) = 0.00142

P(x lesser than or equal to 4) = 0.00000004783 + 0.00011 + 0.00002 + 0.00022 + 0.00142 = 0.00177

c) p = 0.7, q = 0.3

P(x = 5)= 14C5 × 0.7^(14 - 5) × 0.3^5 = 0.19631

6 0
3 years ago
A quadrilateral that has two pairs of Parallel sides and all sides congruent is a:
sweet-ann [11.9K]

Step-by-step explanation:

(square)+(rhombus)..............

4 0
3 years ago
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