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slavikrds [6]
2 years ago
10

What is the area of this triangle?

Mathematics
1 answer:
Nikolay [14]2 years ago
4 0

Answer:13.1

Step-by-step explanation:

Area equation:S=S=\frac{1}{2} ab sinθ

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What is 2.1 as a fraction?
german
2 1/10 because the 1 in 2.1 is in the tenth place
7 0
3 years ago
Find length and width .the lenght is 10 times as long as the width.P=308
patriot [66]

<span>Width(height): x
length of rectangle: 10x 
perimeter: width +width +length +length = 308 inches
or ------- 2width+2length=308
2x+2(10x)=308
2x+20x=308
22x=308</span>

<span>
x=14 the width is 14 inches 
length:
10x
10*14
140 inches 
ANSWER: 
Length:140 inches
Width: 14 inches</span>

8 0
3 years ago
For Tran Please help is appreciate it
Ostrovityanka [42]

Answer:

A = 38°

Step-by-step explanation:

We are going to use cosine law to find angle A where

a = 4.7

b = 3.9 m

c = 2.9 m

{c}^{2}  =  {a}^{2}  +  {b}^{2}  - 2ab \cos(  \alpha )

or

\cos( \alpha  )  =  \frac{ {a}^{2}  +  {b}^{2} -  {c}^{2}  }{2ab}

cos A = [(4.7)^2 + (3.9)^2 - (2.9)^2]/2(4.7)(3.9)

= 28.89/36.66

= 0.788

A = arccos(0.788) = 38°

6 0
3 years ago
Suppose that in one region of the country the mean amount of credit card debt perhousehold in households having credit card debt
kvv77 [185]

Answer:

The probability that the mean amount of credit card debt in a sample of 1600 such households will be within $300 of the population mean is roughly 0.907 = 90.7%.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 15250, \sigma = 7125, n = 1600, s = \frac{7125}{\sqrt{1600}} = 178.125

The probability that the mean amount of credit card debt in a sample of 1600 such households will be within $300 of the population mean is roughly

This probability is the pvalue of Z when X = 1600 + 300 = 1900 subtracted by the pvalue of Z when X = 1600 - 300 = 1300. So

X = 1900

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1900 - 1600}{178.125}

Z = 1.68

Z = 1.68 has a pvalue of 0.9535.

X = 1300

Z = \frac{X - \mu}{s}

Z = \frac{1300 - 1600}{178.125}

Z = -1.68

Z = -1.68 has a pvalue of 0.0465.

0.9535 - 0.0465 = 0.907.

The probability that the mean amount of credit card debt in a sample of 1600 such households will be within $300 of the population mean is roughly 0.907 = 90.7%.

7 0
3 years ago
F(x)=2x(x+1) write in general form
arsen [322]
The general form of a quadratic expression is as follows
f(x) = a {x}^{2} + bx + c

Therefore, the given formula in general form would be:
f(x) = 2x(x + 1)
f(x) = 2x \times x + 2x \times 1
f(x) = 2 {x}^{2} + 2x
3 0
3 years ago
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