The probability that you lose all five times will be 0.59.
<h3>How to calculate the probability?</h3>
From the information given, the chances of winning are 0.1. Therefore, the chance of losing will be:
= 1 - 0.1 = 0.9
Therefore, the probability that you lose all five times will be:
= 0.9 × 0.9 × 0.9 × 0.9 × 0.9
= 0.59
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13 because 40 and 25 would be to long and 8 would be to short
58r=70
r=35/29
r≈1.2069
So the rate was about 1.21 or if you prefer about 20.7%
Answer:
a) 0.3571
b) The p-value is 0.362007.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 1.35
Sample mean, 
= 1.4
Sample size, n = 26
Alpha, α = 0.01
Sample standard deviation, s = 0.7
First, we design the null and the alternate hypothesis
We use One-tailed t test to perform this hypothesis.
a) Formula:
Putting all the values, we have
b) The p-value at t-statistic 0.3571 and degree of freedom 25 is 0.362007.
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
