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2 years ago

Can anyone please help me with this thank you

Mathematics

2 answers:

san4es73 [151]2 years ago

4 0

Answer:

x= 0, and x=4

Step-by-step explanation:

x² -x = 3x, we can subtract 3x from both sides

x² -x -3x = 0, combine like terms

x² -4x = 0 , factor x

x *( x-4) = 0, if the product of 2 numbers equals 0 at least one is 0

x=0 and

x-4 = 0, add 4 to both sides

x= 4

pashok25 [27]2 years ago

4 0

Answer:

x=4 simple thing with all problems like this, is if it has a exponent, then half the exponent and add it to the numerical digit on the right of the equals sign, and you have you answer

Step-by-step explanation:

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krok68 [10]

For Example;
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8 0

2 years ago

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If h(x) = (fºg)(x) and h(x)= 5(x+1)^3 find one possibility for f (x) and g(x).

viktelen [127]

Answer:

One possibility is that;

g(x) = (x + 1)

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Step-by-step explanation:

Here, we are told to find one possibility for f(x) and g(x)

The term h(x) = (Fog)(x) means that we are inserting g(x) into f(x) to give h(x)

Now let’s have it this way;

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6 0

2 years ago

A semi- circle has an area of 35cm . What is its diameter?

patriot [66]

Answer:

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where

r radius of semicircle

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1 year ago

If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), w

Yuliya22 [10]

The value of a is 80

Step-by-step explanation:

The distance of a point $(x_0,y_0)$ from the y-axis can be written as

$d_y = |x_0|$

because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point $(x_0,y_0)$ from the x-axis can be written as

$d_x=|y_0|$

Since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

$d_A = |-30|=30$

- The distance of point B (a,a) from the x-axis can be written as

$d_B = |a| = a$

Since $a>0$ .

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

$\frac{2}{3}d_A = \frac{1}{4}d_B$

Therefore,

$\frac{2}{3}(30)=\frac{1}{4}a$

And solving for a,

$20=\frac{1}{4}a\\a=80$

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

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2 years ago