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Vinvika [58]
3 years ago
14

Can anyone please help me with this thank you

Mathematics
2 answers:
san4es73 [151]3 years ago
4 0

Answer:

x= 0, and x=4

Step-by-step explanation:

x² -x  = 3x, we can subtract 3x from both sides

x² -x -3x = 0, combine like terms

x² -4x = 0 , factor x

x *( x-4) = 0, if the product of 2 numbers equals 0 at least one is 0

x=0 and

x-4 = 0, add 4 to both sides

x= 4

pashok25 [27]3 years ago
4 0

Answer:

x=4  simple thing with all problems like this, is if it has a exponent, then half the exponent and add it to the numerical digit on the right of the equals sign, and you have you answer

Step-by-step explanation:

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insens350 [35]

Answer:

the square root of 64a^2/9b^2+4+32a/3b is

  • ( 8a + 6b ) / 3b

or

  • 8a / 3b + 2

8 0
3 years ago
PLZ HELP PIC INCLUDED​
Reil [10]

x = # of days

y = total calories

Simba = 1000 + 140x = y

Cuddles = 2650 - 190x = y

Let's set both of these equations equal to each other

1000 + 140x = 2650 - 190x

Add 190x to both sides and subtract 1000 from both sides.

330x = 1650

Divide each side by 330

x = 5

After 5 days, they will be consuming the same amount of calories.

To find out how many calories they will be consuming, let's plug 5 into our Simba equation.

1000 + 140(5) = y

Multiply 140 by 5

1000 + 700 = y

Simplify

1700 = y

They will be consuming 1,700 calories each day.

5 0
2 years ago
What is the length of the other diagonal DF?<br> 5 cm<br> 16 cm <br> 21 cm <br> 32 cm
frez [133]
To solve this you need to know Pythagorean theorem.

First, EG is 24, so the halfway points are 12. Knowing Pythagorean triples, you can use 5,12,13 and 12,16,20.

DF = 5+16
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If you don't know Pythagorean triples, I have worked it out on the image attached.

3 0
3 years ago
Read 2 more answers
Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
motikmotik

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

3 0
2 years ago
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zubka84 [21]

Answer: Number one would be 3x+2y+-14 and x+y=-4, second one is x=-3, y=7

Step-by-step explanation:

The first one is solved by inputting the x and y in each one and finding which one comes out true, the second on is solved by substitution. to find x you would subtract x in the first equation and make it y=4-x then input that equation in the y in the second equation.

6 0
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