All categories

2 years ago

Solve. k + 6 > 19

Mathematics

1 answer:

Readme [11.4K]2 years ago

8 0

Answer:

k > 13

Step-by-step explanation:

$k+6 > 19\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:k > 13\:\\ \:\mathrm{Interval\:Notation:}&\:\left(13,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}$

$k+6-6 > 19-6$

$\mathrm{Simplify}$

$k > 13$

Thus, the answer is k > 13

[RevyBreeze]

You might be interested in

Convert 0.00054 to scientific notation

andreev551 [17]

The answer is 5.4 × 10^-4

3 0

3 years ago

Read 2 more answers

Slope that falls between (0,20) and (20,85)

Kipish [7]

Answer:

13/4

Step-by-step explanation:

To find the slope we use the equation

m= (y2-y1)/(x2-x1)

= (85-20)/(20-0)

= 65/20

= 13/4

5 0

3 years ago

What value of x is the solution to the equation: 3x – 7 = x +1 5

Bumek [7]

Answer:

x = 11

Step-by-step explanation:

3x - 7 = x + 15 ( subtract x from both sides )

2x - 7 = 15 ( add 7 to both sides )

2x = 22 ( divide both sides by 2 )

x = 11

3 0

1 year ago

Read 2 more answers

Please help answer this question for me.

Lilit [14]

Answer:

Yes

Step-by-step explanation:

4 0

3 years ago

Flying to Kimpala with a tail wind a plane averaged 158km/hr. On the return trip the plane only average 112km/hr. While flying b

lora16 [44]

The speed of wind and speed of plane in still air are 23 and 135 km/h respectively.

Step-by-step explanation:

Let the speed of wind and speed of plane in still air are w and p km/h respectively.

The effective speed on onward journey was

$p+w=158$ ................(1)

The effective speed on return journey was

$p-w=112$ ..............(2)

Adding equation (1) and equation (2) we get,

⇒ $(p+w)+(p-w) = 158+112$

⇒ $2p = 270$

⇒ $p = 135$

Putting value of $p = 135$ in $p+w=158$ we get:

⇒ $p+w=158$

⇒ $135+w=158$

⇒ $w=23$

Therefore ,The speed of wind and speed of plane in still air are 23 and 135 km/h respectively.

3 0

2 years ago