15% as mixed number in simplest form
1 answer:
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Area of ABC : AB*AC/2
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
hence 
.
We remark that
Hence 4+C=16 thus C=12
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
We remark that
Hence 4+C=16 thus C=12
Sorry, mate but it cannot be solved. m is a complicated number like 
But if you really want the answer, here it is:
m = (5 ± 3
) / 4
If it helps, can you give me the brainliest answer? I need it...
Thank you very much.
But if you really want the answer, here it is:
m = (5 ± 3
If it helps, can you give me the brainliest answer? I need it...
Thank you very much.