(2) (2+5) = 14
2•2= 4
2•5= 10
4+10= 14
Answer:
sin²2θ. (cos θ sin θ). cos 2θ
Step-by-step explanation:
finding g'(x)
g'(x)
= 4 (cosθsinθ)³ . { cosθ. (sinθ)' + sinθ. (cosθ)' }
- (cosθ)' = - sinθ
- (sinθ)' = cosθ
= 4 (cosθsinθ)³ { cosθ. cos θ + sinθ.(-sin θ)}
= 4 (cosθsinθ)³{ cos²θ - sin²θ}
- cos²θ - sin²θ = cos 2θ
- 2sinθ cosθ = sin 2θ
= (4 cosθ sinθ)². (cosθ sinθ). { cos²θ - sin²θ}
= <u>sin²2θ. (cos θ sin θ). cos 2θ</u>
<span>i believe it should be 17 19 and 23 but i could be wrong. </span>
Answer:
Step-by-step explanation:
The answer would be A, since the occurance is based purely on chance
