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svlad2 [7]
3 years ago
10

A hockey team has won a lot of games lately. Because of the recent wins, the coach reasons that the team will likely win the nex

t game. What kind of reasoning did the coach use?
(Points : 1)
inductive reasoning

deductive reasoning

algebraic reasoning

indirect reasoning
Mathematics
2 answers:
Ahat [919]3 years ago
8 0
The coach has used inductive reasoning because he has based his assumption on the results of past events. Inductive reasoning can be defined as the logical reasoning that is based on multiple premises, found true most of the time, to create one conclusion.
Mumz [18]3 years ago
6 0
The coach of the hockey team used inductive reasoning. The correct option among all the options that are given in the question is the first option. Inductive reasoning is basically a decision that is based on events that have happened successfully in the past. I hope the answer has come to your help.
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En una tienda de electrodomésticos, un refrigerador costaba $8,900 y rebajaron su precio a $7,120 ?Cuál fué el porcentaje que le
Mamont248 [21]

Answer:

20\%

Step-by-step explanation:

The question in English is

In one appliance store, a refrigerator cost $8,900 and they lowered it to $7,120. What percentage did they lower?

we know that

$8,900 ------> represent the 100%

so

by proportion

\frac{100\%}{\$8,900}=\frac{x\%}{\$7,120}\\ \\x=7,120*(100\%)/8,900\\ \\x=80\%

therefore

the percentage is equal to

100\%-80\%=20\%

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3 years ago
What is the slope of the line that passes through the points (3,1) and (-2,5)?
viva [34]

Answer:

the answer is d


Step-by-step explanation:


7 0
3 years ago
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Need the answer to this quickly, help!!!
topjm [15]
The answer choice is A
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3 years ago
6. Adlise Leiber started the day with a bank balance of $343.64.
snow_tiger [21]

Answer:

$123.62

Step-by-step explanation:

85.10 + 23.95 + 8.47 = 117.52

117.52 + 100 + 2.50 = 220.02

$343.64 - $220.02 = $123.62

3 0
3 years ago
A thermometer is taken from a room where the temperature is 20◦C to the
lord [1]

Answer:

a) T(2) = 8.265: at time t = 2 minutes the temperature will be 8.265 degress

b) 6 = T(3.55): the temperature will be 6 degrees at time t = 3.55 minutes.

Step-by-step explanation:

When dealing with temperature changes, it's best to work with Newton's Law of Cooling.

T(t) = T_s + Ce^{kt}

here:

T(t) : the temperature in the room.

T_s : ambient (or outdoor) temperature (that always remains constant, in our case: T_s = 5 )

C\,\text{and}\,k: are constants

Our conditions are provided:

1) T(0) = 20

2) T(1) = 12

using the first condition

T(0) = 5 + Ce^{k(0)}\\20 = 5 + C(1)\\C = 15

using the second condition:

T(1) = 5 + Ce^{k(1)}\\12 = 5 + Ce^{k}\\e^k = \dfrac{7}{C}

we can use our calculated value of C to find k

e^k = \dfrac{7}{15}\\k = \ln{(\dfrac{7}{15})}\\k = -0.7621

Finally we can put these constants back in the main equation:

T(t) = T_s + Ce^{kt}

T(t) = 5 + 15e^{-0.7621t} or T(t) = 5 + 15e^{\ln{(\frac{7}{15})t}

a) Reading after one more minute?

so it's asking:

T(2) = ?

T(2) = 5 + 15e^{\ln{(\frac{7}{15})(2)}}\\T(2) = \dfrac{124}{15} \approx 8.267

Hence, after one more minute the temperature of the room will be 8.267 degrees

b) When will it be 6 degrees?

T(t) = 6?

6 = 5 + 15e^{-0.7621t}\\\text{and solve for $t$}\\\\\dfrac{6-5}{15}=e^{\ln{(\frac{7}{15})}t}\\\ln{\left(\dfrac{1}{15}\right)} = \ln{\left(\dfrac{7}{15}\right)t}\\\ln{\left(\dfrac{1}{15}\right)} \div \ln{\left(\dfrac{7}{15}\right)} = t \approx 3.55\\

Hence at t = 3.55 minutes the temperature of the room will be 6 degrees.

8 0
3 years ago
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