Question

Find the equation of a line that passes the points (5, -9) and (0, -3)

Answer 1

Answer:

Y=-6/5x-3

Step-by-step explanation:

Lets convert these two points into slope-intercept form.

We can find the slope with the equation y2-y1/x2-x1=slope.

Insert the values into the equation.

-9-(-3)/5-0=slope

Simplify both sides.

-6/5=slope

The slope is -6/5. To complete equation, we need to find the y intercept.

The y intercept is -3. We know this because x is equal to 0 in this point.

Write it as an equation.

y=(-6/5)x+(-3)

Simplify.

The equation would be y=-6/5x-3

Hope this helps!

Answer 2

Answer:

y = -6/5x - 3

Step-by-step explanation:

Point Slope Form:  (y - y1) = m(x - x1)

Step 1:  Find Slope

m = $\frac{y2-y1}{x2-x1}$

m = $\frac{-3 - (-9)}{0 - 5}$

m = $\frac{-3 + 9}{-5}$

m = $\frac{6}{-5}$

m = $\frac{-6}{5}$

Step 2:  Plug into Point Slope Form

(y - (-3)) = -6/5(x - 0)

y + 3 - 3 = -6/5x - 3

y = -6/5x - 3

Answer:  y = -6/5x - 3