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just olya [345]
2 years ago
11

The coldest temperature recorded on the surface of a planet was - 248 Celsius is the warmest temperature recorded on the surface

of the planet was 108 Celsius what are the correspondence temperatures in degrees Fahrenheit
Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

Answer:

-414.4 F° and 226.4 F°

hope it helps

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Describe the end behavior of a polynomial with a quadratic term with a negative coefficient and a linear term with a positive co
iogann1982 [59]

Answer: I think it’s A

Step-by-step explanation:

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2 years ago
A picture frame can hold a photograph that is 16 inches long and 12 inches wide.
Mila [183]

Answer:

192 inches because 16×12=192

8 0
3 years ago
Question Help Suppose that the lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a
koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So \mu = 5656, \sigma = 333.3

(a) What proportion of light bulbs will last more than 6262 ​hours?

The pvalue of the z-score of X = 6262 is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.

Z = \frac{X - \mu}{\sigma}

Z = \frac{6262 - 5656}{333.3}

Z = 1.82

Z = 1.81 has a pvalue of .96562. This means that 96.562% of the light bulbs are going to last less than 6262 hours. So

P = 100% - 96.562% = 3.438% of the light bulbs will last more than 6262 hours.

​(b) What proportion of light bulbs will last 5252 hours or​ less?

This is the pvalue of the zscore of X = 5252

Z = \frac{X - \mu}{\sigma}

Z = \frac{5252- 5656}{333.3}

Z = -1.21

Z = -1.21 has a pvalue of .1131. This means that 11.31% of the light bulbs will last 5252 hours or less.

(c) What proportion of light bulbs will last between 5858 and 6262 ​hours?

This is the pvalue of the zscore of X = 6262 subtracted by the pvalue of the zscore X = 5858

For X = 6262, we have that Z = 1.81 with a pvalue of .96562.

For X = 5858

Z = \frac{X - \mu}{\sigma}

Z = \frac{5858- 5656}{333.3}

Z = 0.61

Z = 0.61 has a pvalue of .72907.

So, the proportion of light bulbs that will last between 5858 and 6262 hours is

P = .96562 - .72907 = .23655

23.655% of the light bulbs are going to last between 5858 and 6262 hours.

​(d) What is the probability that a randomly selected light bulb lasts less than 4646 ​hours?

This is the pvalue of the zscore of X = 4646

Z = \frac{X - \mu}{\sigma}

Z = \frac{4646- 5656}{333.3}

Z = -3.03

Z = -3.03 has a pvalue of .0012. This means that 0.12% of the light bulbs will last 4646 hours or less.

5 0
3 years ago
What is the volume of the triangular prism shown below ?
jekas [21]

Answer:

B

Step-by-step explanation:

The volume (V) of a triangular prism is

V = area of triangular end × length

area of Δ = \frac{1}{2} bh

where b is the base and h the perpendicular height

here b = 8 and h = 5, so

area = 0.5 × 8 × 5 = 20 units²

the length of the prism is 10, hence

V = 20 × 10 = 200 units³

7 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is a trapezoid with an area of 20 cm^2 Find the height of the trapezoid, h. Round the answer to the nearest t
sergij07 [2.7K]
Area of <span>trapezoid=(7+3)*h/2=20 cm2
10*h/2=20
5h=20
h=4 

the answer is 4.0 cm</span>
5 0
3 years ago
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