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2 years ago

220kg to lb please it's homework

Mathematics

1 answer:

Aleks04 [339]2 years ago

4 0

220 kg * 2.2046= 485.017 lb

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Reduce -10/-5 dont know how too reduce

Agata [3.3K]

Answer:

-10/-5= 2 simply divide

2 negatives multiplied and/ or divided by is a positive number

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2 years ago

40% of b is 65 , what is b

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3 years ago

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Which Expression is equivalent to 4(6 + x + 3x)

Gennadij [26K]

Answer:

=4(6) + 4(X) + 4(3x)

=24+4x+12x

=24+16x

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2 years ago

Factor the Following: 1.) 8 2.) -12 3.) -3y² 4.) 6x²+36x 5.) 7x -14x²

Alex787 [66]

Answer:

1.) 8 = 8

2.) -12 = -12

3.) -3y² = -3y²

4.) 6x² + 36x = 6x(x + 6)

5.) 7x - 14x² = 7x(1 - 2x)

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2 years ago

arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

To find:

The value of $\cos \theta$ .

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

We have,

$\tan\theta =\dfrac{3}{5}$

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

$Hypotenuse=\sqrt{Perpendicular^2+base^2}$

$Hypotenuse=\sqrt{(3x)^2+(5x)^2}$

$Hypotenuse=\sqrt{9x^2+25x^2}$

$Hypotenuse=\sqrt{34x^2}$

$Hypotenuse=x\sqrt{34}$

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{5x}{x\sqrt{34}}$

$\cos \theta=\dfrac{5}{\sqrt{34}}$

Therefore, the value of $\cos \theta$ is $\dfrac{5}{\sqrt{34}}$ .

8 0

2 years ago