Alright
s=number of hours headd south
e=number of hours headed east
s+e=8
and
total is 147 miles
distance=speed times time
15s+24e=147
we got 2 equations
s+e=8
15s+24e=147
subsitution
s+e=8
minus e both sides
s=8-e
subsitut 8-e for s in other equaton
15s+24e=147
15(8-e)+24e=147
120-15e+24e=147
120+9e=147
minus 120 both sides
9e=27
divide both isdes by 9
e=3
sub back
s=8-e
s=8-3
s=5
it was headed south 5 miles
Yes I need points so I’m commenting random stuff lolololo
Step-by-step explanation:
log2x = 1 - log(x+4)
log2x = log10 - log(x+4)
log2x = log[10/(x+4)]
2x = 10/(x+4)
2x(x+4) = 10
2x² + 8x - 10 = 0
÷2 both sides of equation
x² + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5, 1
x isn't be -5 because logA, A need to be > 0
So, x value is 1
Answer:
6x^2-3x
Step-by-step explanation:
Hope this helps!
