<span>If we are to compare which among the given fractions is smaller, we first determine the decimal equivalent of each. If we are to solve for those, we determine that 3/4 is equal to 0.75 and 1/4 is equal to 0.25. This is done by dividing the numerator by the denominator. Comparing 0.75 and 0.25, we can conclude that 0.75 or 3/4 is greater compared to 0.25 or 1/4. </span>
3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
Angles B and D are congruent so:
(360-112-74)/2=87°
Answer:
infinite solutions
Step-by-step explanation:
2x-6 = 3x+1-X-7
Combine like terms
2x-6 = 3x-x +1-7
2x-6 = 2x -6
subtract 2x from each side
-6 = -6
Since this is a true statement, x can be any real number
Sure, each of the following lines.
8x-6+3x-1
11x-6-1
and, 11x-7
