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Fudgin [204]
2 years ago
10

I really need help!!!!!!!!!!!!!!

Mathematics
1 answer:
krek1111 [17]2 years ago
8 0

Answer:

Step-by-step explanation: After purchasing 21 DVDs the membership is worth the money with a total spending of 104 dollars compared to 105 dollars without the membership.

Membership: -20, -24, -28, -32, -36, -40, -44, -48, -52, -56, -60, -64, -68, -72, -76, -80, -84, -88, -92, -96, -100, -104
No Membership: 0, -5, -10, -15, -20, -25, -30, -35, -40, -45, -50, -55, -60, -65, -70, -75, -80, -85, -90, -95, -100, -105

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If the graphs of the equations in a system of linear equations coincide with each other, what does that tell you about the solut
salantis [7]
 If by "coincide", in other words this is also known as intersect, it means that the solution to the system is that intersection point. For instance, if the intersection point of the 2 lines is (5,7) on the graph, it means that in both equations, x = 5 and y = 7. If you mean that the 2 equations result in the same line, it means that the 2 equations were really equal, but that one could be basic to be identical with the other. For example, if you have 2x + 2y = 8 and 4x + 4y = 16, they will give you the same line, and you can see that if you divide that second equation by 2 all the way crossways, it merely shows the first equation.
3 0
3 years ago
Brady used integer chips to model and solve a problem.
nata0808 [166]

Answer:

The answer is "3"

Step-by-step explanation:

In the question, some of the data is missing which is defined in the attached file. please find it.  

\to 7+(-4)\\\\\to 7-4\\\\\to 3

That's why 3 is correct.

6 0
2 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
Help me plz uevdhdb FM xb
Sati [7]

Answer:

a 1/ (6^2)

Step-by-step explanation:

6^3 / 6^6

when dividing exponents we can subtract

6^ (3-6)

6^(-3)

negative exponents go from the numerator to the denominator

1/ (6^3) = 1/216 = 6^-3

1/6^2 is not equal


3 0
3 years ago
Read 2 more answers
The sum of the first and third of three consecutive integers is 140. find the three even integers​
Elina [12.6K]

Answer:

It would be 68,70,72

Step-by-step explanation:

The sum of first and third of 3 consecutive number is 140 as 68+72 is 140.

68 is the first

72 is the third

They are all even numbers as well

6 0
3 years ago
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