All categories

2 years ago

PLEASE HELP 100 POINTS!!!

Mathematics

2 answers:

matrenka [14]2 years ago

8 0

Answer:

See below.

Step-by-step explanation:

The vertex is the point where it stops the arch. In this case, the answer would be (2,2).

-hope it helps

Anon25 [30]2 years ago

6 0

Answer:

B: (2, 2)

Step-by-step explanation:

it's the point where the parabola changes directions

You might be interested in

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0

2 years ago

am and Lou need a total of 1 foot of wire for a science project. Sam’s wire measured 8/12 foot long. Lou’s wire measured 7/8 foo

slamgirl [31]

Answer:

they have enough wire.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Is EFGH below a rectangle

poizon [28]

Answer:

D. No, because EFGH is a parallelogram but it’s diagonals are not congruent

Step-by-step explanation:

The differences between the end points of the diagonals are ...

F -H = (1, 1) -(2, -5) = (1 -2, 1 -(-5)) = (-1, 6)

G -E = (4, -2) -(-1, -2) = (4 -(-1), -2 -(-2)) = (5, 0)

The length of FH is more than 6, the length of GE is exactly 5. The diagonals are different length, so the figure cannot be a rectangle.

The midpoints of the diagonals will be in the same place if the sum of their end points is the same. (Dividing each sum by 2 gives the midpoint of that segment.)

F+H = (1, 1) +(2, -5) = (3, -4)

G+E = (4, -2) +(-1, -2) = (3, -4)

The diagonals bisect each other (have the same midpoint), so the figure is a parallelogram.

EFGH is a parallelogram, but not a rectangle: its diagonals are not congruent.

3 0

2 years ago

If the function 5x + y = 1 has the domain {-2, 1, 6}, then what is the corresponding range?

spayn [35]

Answer:

C. ????

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please help fast! marking brainliest! math!!!

dimaraw [331]

It is the first one 1/3-2 units

3 0

3 years ago

Read 2 more answers