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2 years ago

PLEASE HELP 100 POINTS!!!

Mathematics

2 answers:

matrenka [14]2 years ago

8 0

Answer:

See below.

Step-by-step explanation:

The vertex is the point where it stops the arch. In this case, the answer would be (2,2).

-hope it helps

Anon25 [30]2 years ago

6 0

Answer:

B: (2, 2)

Step-by-step explanation:

it's the point where the parabola changes directions

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I got ace in a week i felt so happy i wanna give someone branliest <br><br> 2+2

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

2 plus 2 equals 4 lmk if you need more help

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2 years ago

Which of the following represents the area of a rectangle whose length is x − 7 and whose width is x + 12? (1 point) a.\x2+x − 8

Nikitich [7]

The answer would be A

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3 years ago

Evaluate

Fittoniya [83]

Answer: 8

Explanation: first start with the fractions. 4 divided by a (which equals 4) is 1. B (which equals 3) divided by 3 is 1. Then put it all together 6+1+1=8.

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3 years ago

Read 2 more answers

Whats the answer to #9 i need help fast!!

vekshin1

I got 784 inches cubed, I cut the figure into two, the first one was 8×4×14=448, the second was 8×3×14=336,
therefore 448+336=784

5 0

3 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

3 years ago