1st
Make a right triangle with legs 5, 12, and hypotenuse D. D is the distance you need.
Pythagorean Th
25 +144 = D^2
169 = D^2
D = 13
2. Plug in all the points...
B, D, F work
<span>4x+10=6x-2
</span>2x = 12
x = 6
Answer:
We have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO.
Step-by-step explanation:
Let us assume that ABCD is a parallelogram having diagonals AC and BD.
We have to prove that in a parallelogram the diagonals bisect each other.
Assume that the diagonals of ABCD i.e. AC and BD intersect at point O.
Therefore, to prove that the diagonals AC and BD bisect each other, we have to first prove that Δ ABO and Δ CDO are congruent or Δ DAO and Δ BCO are congruent.
In symbol, we have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO. (Answer)
Y=6x because once you plug in the x value you’ll get the same y values as in the table
Is 3 times the value
I know this because the number 8 is moved to the left 3 times
