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3 years ago

The questionnnnnnnnn

Mathematics

2 answers:

yanalaym [24]3 years ago

6 0

Answer:

Step-by-step explanation:

C because 25% + 10% = 35% and 10% + 25% is also 35%

CaHeK987 [17]3 years ago

3 0

I’m pretty sure the answer is C

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Find the product and write in lowest term. Give me an integer or simplified fraction. 7/54×27/35

wariber [46]

The product of given expression is $\frac{1}{15} \text{ or } 0.0667$

Solution:

Given that we have to find the product and write it in lowest term

Given expression is:

$\frac{7}{54} \times \frac{27}{35}$

Let us first find common factors of numerator and denominator so, thet simplification becomes easier

$54 = 27 \times 3\\\\35 = 7 \times 5$

Substituting these in above expression, we get

$\rightarrow \frac{7}{27 \times 3} \times \frac{27}{7 \times 5}$

Cancel the common factors in numerator and denominator

$\rightarrow \frac{1}{15}$

In decimal form, we get

$\rightarrow \frac{1}{15} = 0.0667$

Thus the product of given expression is $\frac{1}{15} \text{ or } 0.0667$

4 0

3 years ago

Group health insurance cost $8000, employer pays 80%, employee is paid biweekly. Find the amount deducted each pay for the group

Artyom0805 [142]

The answers is $1600, if this is a multiple choice question.

6 0

3 years ago

Write the following expression as a simplified polynomial in standard form.

LiRa [457]

Answer:

x^2-5x+33

Step-by-step explanation:

(x-4)^2 -5x+20-3

x^2-4^2

6 0

3 years ago

Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha

ella [17]

Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, Î”V=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

∆V = 40.4π ~= 40πft^3

And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

3 0

3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were born

strojnjashka [21]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 335, \pi = \frac{268}{335} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563$

For the percentage:

Multiplying the proportions by 100.

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0

3 years ago