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neonofarm [45]
3 years ago
12

The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What

is the probability that the height of an 18-year-old man selected at random is between 64 inches and 66 inches
Mathematics
1 answer:
Nitella [24]3 years ago
5 0
What is the probability<span> that an </span>18 year old man selected<span> at </span>random<span> is ... what is the </span>probability<span> that the </span>mean height<span> bar x is </span>between<span> 67 and 69 </span>inches<span>? c. ... approx </span>normally distributed<span> with </span>mean 68 inches<span> and std deviation </span>3 inches<span>? a. ... is used in stead of </span>standard deviation<span> as you have a </span>random<span> sample.</span>
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faust18 [17]

Answer:

The equation of the line with slope 6 and containing the point (0, 4) will be:

y = 6x+4

The graph of the line y = 6x+4 is attached below.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

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  • The point (0, 4)

The y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

The point (0, 4) indicates that:

at x = 0, y = 4

Thus, the y-intercept b = 4

now substituting b = 4 and m = 6 in the slope-intercept form of the line equation

y = mx+b

y = 6x+4

Thus, the equation of the line with slope 6 and containing the point (0, 4) will be:

y = 6x+4

The graph of the line y = 6x+4 is attached below.

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3 years ago
What’s 3/6 as a mixed number
earnstyle [38]
0.5

Hope this helped!!
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2 years ago
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What is the 15th term of the sequence -4, -2, 0, 2, …?What is the 15th term of the sequence -4, -2, 0, 2, …?
Dmitriy789 [7]

Answer:

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How can (25√)^2 be rewritten?
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Answer:

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Cards are dealt, one at a time, from a standard 52-card deck. a if the first 2 cards are both spades, what is the probability th
ratelena [41]
So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.

Then third card being spades would be 11 / 50

Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49

Fifth card would be 9 / 48.

So the probability of next three cards being spades would be
\dfrac{11}{50}\cdot\dfrac{10}{49}\cdot\dfrac9{48}=\dfrac{33}{3920}\approx\boxed{0.00842}

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