X actually equals the cube root of 6
![{x}^{3} - 6 = 0 \\ {x}^{3} = 6 \\ x = \sqrt[3]{6}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20%20-%206%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B3%7D%20%20%3D%206%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B6%7D%20)
Answer: JL = 25
Step-by-step explanation: Segment JM is the total measure of the line segment and it equals 45.
Suppose first segment JK measures d.
The total ratio is the sum of each part
d + 4d + 4d = 9d
The sum of each part corresponds to the total measure of the line segment. Then:
9d = 45
d = 5
Segment JL is
JL = d + 4d
JL = 5d
JL = 5.5
JL = 25
Segment JL measures 25 units.
Putting a ladder up against a straight wall. The sides of the triangle are:
1: the ladder
2: the walls
3: the ground from the wall to the ladder
Answer:
x = 2 ±i
Step-by-step explanation:
x^2 = 4x-5
Subtract 4x from each side
x^2 - 4x = 4x-5 -4x
x^2 - 4x= -5
Complete the square
Take the coefficient of the x term, divide by 2 and square it
-4/2 =2 2^2 =4
Add 4 to each side
x^2 -4x+4 = -5 +4
The left side is (x-coefficient of the x term/2)^2
(x-2)^2 = -1
Take the square root of each side
sqrt((x-2)^2) = sqrt(-1)
x-2 = ±i
Add 2 to each side
x-2+2 = 2 ±i
x = 2 ±i
