The intersection line of two planes is the cross product of the normal vectors of the two planes.
p1: z=4x-y-13 => 4x-y-z=13
p2: z=6x+5y-13 => 6x+5y-z=13
The corresponding normal vectors are:
n1=<4,-1,-1>
n2=<6,5,-1>
The direction vector of the intersection line is the cross product of the two normals,
vl=
i j k
4 -1 -1
6 5 -1
=<1+5, -6+4, 20+6>
=<6,-2,26>
We simplify the vector by reducing its length by half, i.e.
vl=<3,-1,13>
To find the equation of the line, we need to find a point on the intersection line.
Equate z: 4x-y-13=6x+5y-13 => 2x+6y=0 => x+3y=0.
If x=0, then y=0, z=-13 => line passes through (0,0,-13)
Proceed to find the equation of the line:
L: (0,0,-13)+t(3,-1,13)
Convert to symmetric form:

=>
Option (4.) is the answer angel TRS......
12/x = 52/48
12 * 48 = 52x
x = 11.07 This is one way to do it.
Let the time = x
Let the part of the lawn = y
The general equation
y = k*x
52/100 = k * 12
k = 0.043333
y = 0.043333*x
y = 0.043333* 11.08
y = 0.48 which is what it should be.
Yet another way is to let y = kx
52 = k*12
k = 52/12
k = 4.33333333
y = 4.333333 * x
y = 4.333333 * 48
48 = 4.333333 * x
x = 11.07 which is just what you should expect.
Assuming that the 4.8% interest rate is an annual interest rate, then, after one year, with a principal of $3,000 we would be able to win 4.8% of $3000:

Divide 144 over 12 to find the monthly earnings:

Therefore, with a principal of $3,000 we would be earning $12 interest in 1 month.
For the earnings on the first month to be equal to $10, then you would have to win $120 annually, and $120 must be 4.8% of the principal. To find which quantity satisfies that 4.8% of it is equal to $120, divide 120 over 4.8%:

Therefore, the principal must be equal to $2500 for you to win $10 on the first month, and it would indeed be correct to say that if you open an account with $3000 you will earn at least $10 interest in 1 month.