Which expression is equivalent to 113−−−√5?

Compare the measures of the different angles of elevation and depression that are labeled in the diagram. Which statements are t

Rudik [331]

The statements that are true about the angle include:

x > y

w = y

y < v

<h3>How to illustrate the information?</h3>

From the information, the first has legs 529m and 229m. Then tan x = 529/229. Also tan y = 529/347.

It can be seen that tan x is greater than tan y. Angles x, v, y, and w are alternate angles. Therefore, the correct options are A, C, avd D.

A weather balloon is 529 meters above the ground. Two weather stations, A and B, monitor the balloon’s progress. Compare the measures of the different angles of elevation and depression that are labeled in the diagram. Which statements are true

Learn more about angles on:

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3 0

2 years ago

Geologist has collected 10 specimens of basaltic rock and 10th specimens of granite. The geologist instructs a laboratory assist

olya-2409 [2.1K]

Answer:

$p(5)=0.00136$

(a) $p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}$

(b) $p(10)+p(5)=0.00272$

(c) $p(7)+p(8)=0.0584$

Step-by-step explanation:

If we have N elements with k elements that we consider success and N-k elements that we consider fail, and we take a sample of n elements, the probability that there are x successes in the sample follows a hypergeometric distribution, so it is calculated as:

$p(x)=\frac{(kCx)*((N-k)C(n-x))}{NCn}$

In this case, N is equal to 20, k is equal to 10 specimens of granite rock, N-k is equal to 10 specimens of basaltic rock and n is 15. So, the probability that there are x specimens of granite rock in the sample or the pmf of the number of granite specimens selected for analysis is:

$p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}$

Now, the probability of getting exactly 5 granite specimens selected for analysis is:

$p(5)=\frac{(10C5)*((10)C(15-5))}{20C10}=0.00136$

On the other hand, the probability that all specimens of one of the two types of rock are selected for analysis is the probability to select 10 granite specimens or 10 basaltic specimens. Where the probability to take 10 basaltic specimens is equal to the probability to take 5 granite specimens.

Then, the probability that all specimens of one of the two types of rock are selected for analysis is:

$p(10)+p(5)=\frac{(10C10)*((10)C(15-10))}{20C10}+\frac{(10C5)*((10)C(15-5))}{20C10}\\p(10)+p(5)=0.00136+0.00136=0.00272$

For the hypergeometric distribution, the mean E(x) and standard deviation S(x) are:

$E(x)=\frac{nk}{N}=\frac{15*10}{20}=7.5\\S(x)=\sqrt{\frac{nk}{N}*(1-\frac{k}{N})*(\frac{N-n}{N-1})}\\S(x)=\sqrt{\frac{15*10}{20}*(1-\frac{10}{20})*(\frac{20-15}{20-1})}=0.9934$

Then, the number of granite specimens within 1 standard deviation of its mean value is:

E(x) - S(x) ≤ mean ≤ E(x) + S(x)

7.5-0.9934 ≤ mean ≤ 7.5+0.9934

6.5066 ≤ mean ≤ 8.4934

7 ≤ mean ≤ 8

Finally, the probability that the number of granite specimens selected for analysis is within 1 standard deviation of its mean value is:

$p(7)+p(8)=\frac{(10C7)*((10)C(15-7))}{20C10}+\frac{(10C8)*((10)C(15-8))}{20C10}\\p(10)+p(5)=0.0292+0.0292=0.0584$

8 0

4 years ago

The owner of a resale shop is analyzing the revenue for the year. Profit is modeled by the function p(x) = x2 – 14x + 485, where

Gnom [1K]

what you got to do is you have to pee X 2 which which will give you an answer and you will subtracted by 4 + 485 which will give u p xthen you have your answer you can do it backwards like pee times 485 + 14 * -2 equals P x

3 0

3 years ago

What is the length of the radius of a circle with a center at 2 – i and a point on the circle at 8 + 7i?

Vesnalui [34]

Answer:

10

Step-by-step explanation:

The radius is the magnitude of the complex number that is the difference between any point on the circle and the center point. A suitable calculator can tell you that magnitude:

║(8+7i) - (2-i)║ = √((8-2)² +(7-(-1))²) = √(36+64) = √100 = 10

7 0

3 years ago

Read 2 more answers

Can anyone explain this to me please

timurjin [86]

Hello there,

To start it off, 2 x 39= 78
So a is correct that would be 2 x 30+9 = 2x39= 78
So b is correct as well. 2 x 40-1= 2 x 39= 78
c is questionable 2 x 30 +9= 60 + 9 = 69
So d is correct 18 + 60 = 78
So e is correct 100-22 = 78

So 2 x 39 is not equal to (2 x 30) +9

Hope this helped!

5 0

3 years ago