4.43
To find the mean (average) # of sick days taken, you add all the numbers, then divide by the number of employees.
31 ÷ 7 = 4.4285714286 or aprox. 4.43
Answer:
- See the graphs attached and the explanation below
Explanation:
The most simple sine function, considered the parent function, is:

That function has:
- Midline, also known as rest or equilibrium position: y = 0
- Minimum: - 1
- Maximum: 1
- Amplitude: the distance between a minimum or a maximum and the midline = 1
- period: the interval of repetition of the function = 2π
The more general sine function is:

That function has:
- Midline: y = D (it is a vertical shift from the parent function)
- Minimum: - A + D
- Maximum: A + D
- Amplitude: A
- period: 2π/B
- phase shift: C (it is a horizontal shift of the from the parent function)
Now, you have to draw the sine function with the given key features:
- Period = 4 ⇒ 2π/B = 4 ⇒ B = π/2
- midline y = - 1 ⇒ D = - 1
Substitute the know values and use the y-intercept to find C:

Substitute (0, -1)

Hence, the function to graph is:

To draw that function use this:
- Maxima: 3(1) - 1 = 3 - 1 = 2, at x = 1 ± 4n (n = 0, 1, 2, 3, ...)
- Minima: 3(-1) - 1 = - 3 - 1 = -4
- y-intercept: (0, - 1)
- x-intercepts: the solutions to 0 = 3sin(πx/2) = - 1
- first point of the midline: (0, -1) it is the same y-intercept
With that you can understand the graphs attached.
The height of the Washington monument is 555.146.
I got this by using trigonometry “tan(77) • 118”
Answer:
B) The heights of the bear should equal the class frequency.
Step-by-step explanation:
In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.
Answers:
- a) x = 9
- b) arc JK = 68
- c) arc MJ = 112
- d) arc LMK = 248
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Explanation:
Arcs JK and KL form a semicircle, so they add to 180 degrees
(arcJK) + (arcKL) = 180
(5x+23) + (17x-41) = 180
22x-18 = 180
22x = 180+18
22x = 198
x = 198/22
x = 9
Then you'll use this x value to find arc JK and arc KL
arc JK = 5x+23 = 5*9+23 = 68
arc KL = 17x - 41 = 17*9-41 = 112
Since central angles MNJ and KNL are vertical angles, this means minor arcs MJ and KL are congruent arcs. So arc MJ is also 112 degrees
Arc LMK is basically nearly everything of the full circle, but we exclude out the portion from L to K (the shorter distance)
arc LMK = (full circle) - (measure of minor arc LK)
arc LMK = 360 - 112
arc LMK = 248