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AleksandrR [38]
3 years ago
15

Nicole sold 1 cherry pie and 9 pumpkin pies for $60. Lisa sold 11 cheery pies and 4 pumpkin pies for $90. what's the cost each o

f one cherry pie and one pumpkin pie?
Mathematics
1 answer:
zubka84 [21]3 years ago
3 0
X= cost per cherry pie
y= cost per pumpkin pie

NICOLE
1x + 9y= $60

LISA
11x + 4y= $90


STEP 1
multiply Nicole's equation by -11

-11(1x + 9y)= -11($60)
multiply -11 by all terms

(-11 * x) + (-11 * 9y)= (-11 * 60)

-11x - 99y= -660


STEP 2
add Nicole's new equation from step 1 to Lisa's equation to solve for y (using the elimination method)

-11x - 99y= -660
11x + 4y= 90
the x terms "cancel out"

-95y= -570
divide both sides by -95

y= $6 per pumpkin pie


STEP 3
substitute y value into either original equation to solve for x

x + 9y= $60

x + 9(6)= 60

x + 54= 60
subtract 54 from both sides

x= $6 per cherry pie


CHECK
11x + 4y= $90
11(6) + 4(6)= 90
66 + 24= 90
90= 90


ANSWER: Each cherry pie costs $6 and each pumpkin pie costs $6.

Hope this helps! :)
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Answer:

22 or 4+12+6

Step-by-step explanation:

Since A is equal to 2, times 2 by 2 and get 4

Since B= 4 you times 3 by 4 and get 12

4+12 is 16

16 plus 6 is 22

5 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
Read 2 more answers
Hộp đựng 3 bi đỏ, 5 bi trắng và 7 bi xanh lấy ngẫu nhiên 2 bi. Tính xác suất? a, Có 1 bi đỏ trong 2 bi lấy ra b, Có ít nhất 1 bi
Vikentia [17]

Answer:

a) 3C1 * 12 C1 / 15 C2

b)  1 - 12C2 / 15C2

Step-by-step explanation:

Được

Viên bi đỏ = 3

Viên bi trắng = 5

Viên bi xanh = 7

Hai quả bóng được rút ra một cách ngẫu nhiên

a) Có 1 bi đỏ

3C1 * 12 C1 / 15 C2

b) Có ít nhất 1 viên bi đỏ trong số 2 viên lấy ra.

Số kết quả của việc chọn hai quả bóng trong số 15 quả bóng = 15 C2

Số kết quả của việc chọn 0 quả bóng đỏ = 15C12

Xác suất chọn được ít nhất 1 viên bi đỏ = 1 - 12C2 / 15C2

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grandymaker [24]

Answer: That's 16 i hope this helps

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