Answer:
176 199 pounds
Step-by-step explanation:
To answer this it is first useful to find the proportionality constant.
F= kx
8080 pounds = k.88 in
k = 91.81 pound/inch
So what force is required to stretch the spring to 1919 inches?
F = kx
= 91.81 pound/inch * 1919 inches
= 176 199 pounds
It is worth noting that this force seems rather large and the spring might have long reached its elastic limit
We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k







............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k




Since, this is absolute function
so, we can break it into two parts


we get




so,
...............Answer
Answer:
B is the answer
Step-by-step explanation:
(2m5n4)3
2mx3=6m
5nx3=15n
4x3=12
6m15n12
Tell me if im right :)
To estimate, you can round 627 up to 630 and round 253 down to 250.
650-250=380. 380 is your estimate.
The actual answer is 374.