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Brut [27]
2 years ago
14

50 POINTS FOR CORRECT ANSWER!

Mathematics
2 answers:
aev [14]2 years ago
8 0
  • (0,3)
  • (-3,-3)

Slope:-

\\ \tt\Rrightarrow m=\dfrac{-3-3}{-3}=2

Equation of line in point slope form

\\ \tt\Rrightarrow y-3=2x

\\ \tt\Rrightarrow y=2x+3

Put (0,0)

  • 2(0)+3=3>0

Hence the inequality is

\\ \tt\Rrightarrow y\geqslant 2x+3

qaws [65]2 years ago
7 0

Answer:

y\geq 2x+3

Step-by-step explanation:

the gradient of a line is found by using the formula \frac{y_{2}-y_{1}}{x_{2}-x_{1} }

so we get \frac{5-3}{1-0}=\frac{2}{1} =2

the y-intercept is where the line crosses the y-axis which is simply 3

so the equation of this line is y=2x+3 in the form y=mx+c

but the question is asking for an inequality, specifically above the line so we get y\geq 2x+3

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The domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}

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Given the following functions:

f(x)=\frac{9}{x^2-9}\\g(x)=x+3

First we need to get the composite function f(g(x))

f(g(x)) = f(x+3)\\f(x+3)=\frac{9}{(x+3)^2-9} \\f(x+3)=\frac{9}{x^2+6x+9-9} \\f(x+3)=\frac{9}{x^2+6x} \\

Get the domain

The domain the values of x for which the function exists. The function cannot exists at when x = -6 and x = 0

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Learn more here: brainly.com/question/20838649

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