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Schach [20]
2 years ago
12

¿Qué es 1/3 x5 / 6? ¿Qué es 2/5 x 3/7?​

Mathematics
1 answer:
Talja [164]2 years ago
7 0

Answer:divicionsumrestnwufoifriuwhsih

Step-by-step explanation:

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Need help on this pls
aliya0001 [1]
The answer to the question is A
4 0
2 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
heights of statistics students were obtained by a teacher as part of an experiment conducted for the class. The last digit of th
hammer [34]

Answer:

1) B. The height appear to be reported because there are disproportionately more 0s and 5s.

2) A. They are likely not very accurate because they appear to be reported.

Step-by-step explanation:

The distribution table is shown below:

Last Digit           Frequency

     0                          9

     1                           1

     2                          1

     3                          3

     4                          1

     5                         11

     6                          1

     7                          0

     8                          3

     9                          1

1. Based on the distribution table, we see a very disproportionate distribution. There is a high frequency of 0's and 5's. This lays credence to the heights being reported rather than measured. As such, option B is the correct answer

<u>B. The height appear to be reported because there are disproportionately more 0s and 5s</u>.

2. Since the heights were reported and not measured, they are most certainly not accurate. The conclusion is that the result is not accurate. As such, option A is the correct answer

<u>A. They are likely not very accurate because they appear to be reported</u>.

7 0
3 years ago
The u.s. dairy industry wants to estimate the mean yearly milk consumption. a sample of 16 people reveals the mean yearly consum
lidiya [134]
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.

3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75

4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)

5. Since the interval include 63, it is reasonable.
3 0
2 years ago
Michelin Tire Company wishes to set a minimum mileage guarantee on its new MX100 tire. Tests reveal the mean mileage is 67,900 w
Keith_Richards [23]

Answer:

The minimum guaranteed mileage is  x = 71489.55

Step-by-step explanation:

From the question we are told that

   The mean is  \mu  =  67900

     The standard deviation is  \sigma =  2050

Generally for the probability to be 4% the minimum guaranteed mileage is evaluated as

    P( X  \ge x ) =1-  P( \frac{X - \mu }{\sigma } < \frac{ x -  67900 }{ 2050}  ) = 0.04

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

     P( X  \ge x ) =1-  P( Z

=>  P( X  \ge x ) = P( Z

=>    z = \frac{ x -  67900 }{ 2050}

From the z table, the critical value corresponding to 0.96 to the left of the curve is  

         z = 1.751

So

        1.751 = \frac{ x -  67900 }{ 2050}

=>     x = 71489.55

4 0
3 years ago
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