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Answer: </u><em>122151</em></h2><h3 /><h3>
<em>no it is not okay for someone to do that behind the person their datings back honestly. i have had this happen to me by one of my ex boyfrie.nds and it does bother me that i let him hur.t me like that but no it isnt okay and you should never let it slide cause they could always do it again.</em></h3>
The are 8 blue bicycles, 6 green bicycles, and 4 yellow bicycles and total they equal 18.
Answer:
The 95% confidence interval of the proportion of all adults that have high blood pressure is 0.17059 < < 0.314695
Step-by-step explanation:
The confidence interval for a proportion is given by the following formula;
Where:
x = 33
n = 136
= x/n = 33/136 = 0.243
z value for 95% confidence is 1.96
Plugging in the values, we have;
Which gives;
0.17059 < < 0.314695
Hence the 95% confidence interval of the proportion of all adults that have high blood pressure = 0.17059 < < 0.314695
From the above we have;
23.2 < x < 42.798
Since we are dealing with people, we round down as follows;
23 < x < 42.
Answer:
The area in factored form is .
The area in standard form is .
Step-by-step explanation:
The area of a rectangle is length times width.
So the area here is (x+2)(x-5).
They are probably not looking for A=(x+2)(x-5) because it requires too little work.
They probably want A in standard form instead of factored form.
Let's use foil:
First x(x)=x^2
Outer: x(-5)=-5x
Inner: 2(x)=2x
Last: 2(-5)=-10
---------------------Adding together: .
The area in factored form is .
The area in standard form is .
Answer:
The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.
Step-by-step explanation:
We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.
The probability of k online retail orders that turn out to be fraudulent in the sample is:
We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:
The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.