Answer:not 100%
Explanation:
What we’re the options for 5 and 9
The anwser is a. look it up or sum idek it fr
Fixation during which the enzyme RuBisCO incorporates (fixes) carbon-dioxide into 3-PGA; 2. Reduction during which 3-PGA is reduced using NADPH as electron supply; 3. Regeneration during which RuBP<span> is regenerated so the cycle can start again.</span>
Answer:
1. At the end of S phase- 20 pg DNA
2. At the end of G2 phase- 20 Pg DNA
Explanation:
The cell before undergoing M phase undergoes the steps of interphase that is G₁, S and G₂ phase.
During S phase, the process of cell replication takes place which replicates the DNA as a result of which the amount of DNA doubles. This DNA amount is reduced to half during the anaphase stage of M phase.
In the question since the amount of DNA is 10pg therefore the amount will be double during S phase and becomes 20 pg and will remain 20 pg until the DNA is distributed therefore at the end of G₂ phase Will remain the 20 pg.
