Given:
The expressions are:
To find:
The product of each expression.
Solution:
According to the distributive property of multiplication over addition, we get
The first expression is:
Using distributive property of multiplication over addition, we get
Therefore, the product of is 
.
The second expression is:
Using distributive property of multiplication over addition, we get
Therefore, the product of is 
.
(x+3)(x+1)=(x+6)(x)
x^2+x+3x+3=x^2+6x
x^2+4x+3=x^2+6x
4x+3=6x
3=2x
x=1.5
Hope this helps :)
Hello from MrBillDoesMath!
Answer: x = 1
Discussion
:
Per the author, the equation to solve is 12 = 5x + 7
Isolate the "x" variable by subtracting 7 from both sides of the equation:
12 = 5x + 7
-7 = -7
---------------------
12-7 = 5x + 0
or
5 = 5x
Dividing both sides by 5 gives x - 1
Regards, MrB
<span>If x= side of the square, and A = area of square, then
A = x^2
dA/dx = 2x, or
dA = 2x*dx, where dx is the differential in x (same as error)
dA/A = 2x*dx/(x^2) = 2*dx/x = 2*(0.05cm)/(15cm) = 0.00667 = 0.667%
for b):
if dA/A = 0.025 = 2*dx/x, then
dx/x=(0.025)/2 = 0.0125 = 1.25 %
I hope I helped. :)</span>
