Answer:
Acute isosceles triangle!
Step-by-step explanation:
Hope this helps! :]
Answer: 
Step-by-step explanation:
To polygons are said to be similar if all the corresponding angles of given polygons are equal.
In the given figure, it can be seen that in quadrilateral FSHB and quadrilateral KTWJ all the corresponding angles are equal.
∠F=∠K
∠S=∠T
∠H=∠W
∠B=∠J
Therefore, The given polygons are similar.
Hence,
The difference in distance between Aero plane A and B is; 34.67 km
<h3>How to calculate bearing?</h3>
To get the bearing;
∠H = (115 - 90) + (270 - 203)
∠H = 92°
Then, we will use cosine rule to get the distance between both Planes A and B.
d_ab = √(18² + 29² - 2(18 * 29) * cos 92)
d_ab = √(324 + 841 + 36.435)
d_ab = 34.67 km
Read more about bearing at; brainly.com/question/22518031
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Answer:
1) (2,4)
2) (5,-2)
Step-by-step explanation:
those are the points at which the lines cross making them the solutions to the equations
3x greater than or equal to 20
3x = 20
X= 7 games for the pass to be better
3(7)=21
