Answer:
It's change of subject. :)
B the person above me is right
Answer:
7 square units
Step-by-step explanation:
As with many geometry problems, there are several ways you can work this.
Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.
The applicable formulas are ...
area of a trapezoid: A = (1/2)(b1 +b2)h
area of a triangle: A = (1/2)bh
So, our areas are ...
AQRS = AWSQE - AWSR - AEQR
= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)
Factoring out 1/2, we have ...
= (1/2)((2+5)·4 -2·2 -5·2)
= (1/2)(28 -4 -10) = 7 . . . . square units
ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).
<em><u>Recall:</u></em>
- A segment that divides an angle into equal parts is known as an angle bisector.
- Two triangles are congruent by the ASA Congruence Theorem if they share a common side and have two pairs of congruent angles.
In the diagram given, Angle bisector, GE, divides ∠HEF into congruent angles, ∠HEG ≅ ∠GEF.
Also divides ∠FGH into congruent angles, ∠HGE ≅ ∠FGE.
Both triangles also share a common side, GE
<em>This implies that: ΔHGE and ΔFGE have:</em>
two pairs of congruent angles - ∠HEG ≅ ∠GEF and ∠HGE ≅ ∠FGE
a shared side - GE
Therefore, ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).
Learn more about ASA Congruence Theorem on:
brainly.com/question/82493
