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xz_007 [3.2K]
3 years ago
10

Loretta is rolling an unfair 6 sided die with a single number between 1 and 6 on each face. She has a 70% chance of rolling a fo

ur. She is playing a game with a friend and knows that if she rolls a four on three of her next five rolls she will lose the game. She wants to determine the probability that she rolls a four on three of her next five rolls.
Which simulation design has an appropriate device and a correct trial?
A) Using a fair coin let heads represent rolling a four and tails represent not rolling a four. Flip the coin five times.
B) Using a table of random digits select a digit between 0 and 9. Let 0-6 represent rolling a four and 7-9 represent not rolling a four. Select five digits.
C) Roll a fair die with a single digit between 1 and 6 on each face. Let four represent rolling a four and 1-3 and 5 and 6 represent not rolling a four. Roll the die five times.
D) Using a table of random digits select a digit between 1 and 6, ignoring digits 0, 7, 8, and 9. Let 4 represent rolling a four and 1-3 and 5 and 6 represent not rolling a four Select five digits.
Mathematics
1 answer:
coldgirl [10]3 years ago
5 0

Answer:

The answer is option B.

Step-by-step explanation:

Loretta is rolling an unfair 6 sided die with a single number between 1 and 6 on each face and she has a 70% chance of rolling a four.

She is playing a game with a friend and knows that if she rolls a four on three of her next five rolls she will lose the game.

She wants to determine the probability that she rolls a four on three of her next five rolls.

The simulation design that is helpful here is :

B) Using a table of random digits select a digit between 0 and 9. Let 0-6 represent rolling a four and 7-9 represent not rolling a four. Select five digits.

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\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
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now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
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b=opposite\\
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let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
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c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
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