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romanna [79]
2 years ago
6

Brandon rolls a six sided die twenty times, and records the result in the table below. how many times did brandon roll above the

average? 6 1 3 4 4 4 6 5 5 3 6 4 4 5 2 3 5 4 4 2 a. 14 b. 7 c. 5 d. 4
Mathematics
1 answer:
Radda [10]2 years ago
8 0

The average is the arithmetic mean of all the observations of a set of numbers. The number of times Brandon rolls above the average is 7.

<h3>What is average?</h3>

The average is the arithmetic mean of all the observations of a set of numbers. it is found by dividing the sum of all the observations of the set by the number of observations in the set.

\rm{Average=\dfrac{Sum\ of\ observations}{Number\ of\ observations}

In order to know the number of times Brandon rolls the dice above the average, we first need to calculate the average of the twenty rolls.

The average of the 20 times dice rolls,

\rm Average = \dfrac{6+1+3+4+4+4+6+5+5+3+6+4+4+5+2+3+5+4+4+2}{20}

\rm Average = \dfrac{80}{20} = 4

Thus, the average of the 20 rolls of the dice is 4.

Now, the number of times the result of the dice roll is above 4(x>4) is 7.

Hence, the number of times Brandon rolls above the average is 7.

Learn more about Average:

brainly.com/question/2426692

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Bas_tet [7]
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62.5x      x          x
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100      100      100

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(b)  Ship travels 62.5 in first hour then  this falls by a common ratio of 0.8 each hour so we have a geometric sequence 

Dist travelled in 6 hours  =  a1  1 - r^n
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                                               1 - r

Answer is    230.56 km 




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3 years ago
A vase has the shape of a rectangular prism. The inside of the vase is also a rectangular prism. What is the volume of the solid
saw5 [17]

Answer:

V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)

Step-by-step explanation:

The geometric description of the vase is described in the image attached below. The volume of the solid part of the vase is:

V_{s} = V_{out} - V_{in}

V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)

Where:

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