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liraira [26]
3 years ago
12

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and h

otdogs and made $420. How many of each did they sell? Which system of equations matches the situation?
Mathematics
2 answers:
Andrei [34K]3 years ago
8 0

Answer:

Number of hamburgers = 120

Number of hotdogs = 180

Step-by-step explanation:

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1.

On Friday night they sold a total of 300 hamburgers and hotdogs and made $420.

We have to find the numbers of hamburgers and hotdogs.

Now we have to form the equations

h + d = 300------(1)

2h + 1d = 420-------(2)

By subtracting equation 2 from 1.

2h + d - h - d = 420 - 300

h = 120

and from equation 1

d + 120 = 300

d = 300 - 120 = 180

Therefore total 120 hamburgers and 180 hotdogs were sold.

guajiro [1.7K]3 years ago
5 0
A) 2h+d=420. b) h+d=300. Subtract b) from a). h+0=120 so h=120. You sold 120 hamburgers. And so you must have sold 180 hotdogs.
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