Answer with Step-by-step explanation:
Let a and b are two integers.
We have to show that
if 3\a+b then 3\a-b is false.
In order to prove that given statement is false we prove this with the help of example
Suppose we have two integers a=2 and b=4
if 3\2+4
3\6=2
2-4=-2
But 3 does not divide -2.
Therefore, the given statement is false.
Hence, proved.
Answer:
Multiply each equation by the value that makes the coefficients of
x
opposite.
(
−
3
)
⋅
(
2
x
+
5
y
)
=
(
−
3
)
(
20
)
(
2
)
⋅
(
3
x
−
10
y
)
=
(
2
)
(
37
)
Step-by-step explanation:
Answer:
w=14
Step-by-step explanation:
29-15=14
1. sqrt(98) = 7 sqrt(2)
2. sqrt(y^6) = y^3
3. sqrt(a^7) = a^7/2
4. sqrt(12x^3y^2) = 2xy sqrt(3x)
5. sqrt(36x^2y^4) = 6xy^2
6. sqrt(48ab^3) = 4b sqrt(3ab)
7. sqrt(10a^5b^2) = a^2b sqrt(10a)
8. sqrt(20x^3y^10 = 2xy^5 sqrt(5x)
So just add 1/8 and 2/8. add 1 plus 2 and the denominator (bottom number) stays the same so you get 3/8 then subtract 8/8 minus 3/8 so just 8 minus 3 is 5 and the denominator stays the same so you end up with 5/8 so 5/8 of the book remains unread
