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3 years ago

Find the 97th term of the arithmetic sequence

Mathematics

1 answer:

kozerog [31]3 years ago

3 0

<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1 = 25

The difference between two terms, d = 29 - 25 = 4

To find the 97th term,

By formula, $a_{n} = a_{1} + (n - 1) d$

Substituting the values in the above equation, we get

$a_{97} = 25 + (97 - 1) 4$

= 25 + (96 * 4)

= 25 + 384

= 409

The 97 th term in the given sequence is 409.

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Step-by-step explanation:

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3 years ago

F(x) = 4x² + 5x - 3<br> g(x) = 4x³<br> 3x² + 5<br> Find (f+g)(x).

Dmitriy789 [7]

Answer:

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Step-by-step explanation:

Given:

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2 years ago

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NeX [460]

1) Which ratio is equivalent to [tex] \frac{4}{16} [tex]?
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3 years ago

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neonofarm [45]

Answer:

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(Anything to the power of 0 = 1)

and 6 to the power of -1 = 1/6

( Any number to the power of a negative number will become a fraction)

Example.

$5^{ - 3} = \frac{1}{5^{3} }$

So is will be 1/6 over 1

Which gives you your final answer.

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2 years ago

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baherus [9]

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3 years ago