1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
3 years ago
12

Order -3,5, 16, and -10 from least to greatest.

Mathematics
1 answer:
Furkat [3]3 years ago
6 0
Least to greatest: -10, -3, 5, 16
Closet to farthest from 0: -3, 5, -10, 16
You might be interested in
Name the quadrant in which the angle is in cos theta>0, csc theta<0
bekas [8.4K]

Answer:

Quadrant 4

Step-by-step explanation:

Csc = 1/sin

Cos is positive in quadrants 1 and 4

Sin is negative in quadrants 3 and 4

7 0
4 years ago
LINEAR ALGEBRA
kenny6666 [7]

Answer:

The value of the constant k so that \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{2} is \frac{7}{10}.

Step-by-step explanation:

Let be \vec u_{1} = [2,3,1], \vec u_{2} = [4,1,0] and \vec u_{3} = [1, 2,k], \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{3} if and only if:

\alpha_{1} \cdot \vec u_{1} + \alpha_{2} \cdot \vec u_{2} +\alpha_{3}\cdot \vec u_{3} = \vec O (Eq. 1)

Where:

\alpha_{1}, \alpha_{2}, \alpha_{3} - Scalar coefficients of linear combination, dimensionless.

By dividing each term by \alpha_{3}:

\lambda_{1}\cdot \vec u_{1} + \lambda_{2}\cdot \vec u_{3} = -\vec u_{3}

\vec u_{3}=-\lambda_{1}\cdot \vec u_{1}-\lambda_{2}\cdot \vec u_{2} (Eq. 2)

\vec O - Zero vector, dimensionless.

And all vectors are linearly independent, meaning that at least one coefficient must be different from zero. Now we expand (Eq. 2) by direct substitution and simplify the resulting expression:

[1,2,k] = -\lambda_{1}\cdot [2,3,1]-\lambda_{2}\cdot [4,1,0]

[1,2,k] = [-2\cdot\lambda_{1},-3\cdot \lambda_{1},-\lambda_{1}]+[-4\cdot \lambda_{2},-\lambda_{2},0]

[0,0,0] = [-2\cdot \lambda_{1},-3\cdot \lambda_{1},-\lambda_{1}]+[-4\cdot \lambda_{2},-\lambda_{2},0]+[-1,-2,-k]

[-2\cdot \lambda_{1}-4\cdot \lambda_{2}-1,-3\cdot \lambda_{1}-\lambda_{2}-2,-\lambda_{1}-k] =[0,0,0]

The following system of linear equations is obtained:

-2\cdot \lambda_{1}-4\cdot \lambda_{2}= 1 (Eq. 3)

-3\cdot \lambda_{1}-\lambda_{2}= 2 (Eq. 4)

-\lambda_{1}-k = 0 (Eq. 5)

The solution of this system is:

\lambda_{1} = -\frac{7}{10}, \lambda_{2} = \frac{1}{10}, k = \frac{7}{10}

The value of the constant k so that \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{2} is \frac{7}{10}.

4 0
4 years ago
HELP PLZ AGAIN. Same material. It is still timed. Will give 100 pts and brainly. This is vital to my math grade. Time is on the
ruslelena [56]

Answer:

y=4x+47

I wanted to wait for the person who originally said the answer but it's been a while and I kinda want the points. Sorry

6 0
3 years ago
Read 2 more answers
Can someone solve this
Bond [772]

Answer:

-1/2

Step-by-step explanation:

8 0
3 years ago
Write an equation of a parabola that opens to the left, has a vertex at the origin, and a focus at (–9, 0.
Georgia [21]
The standard equation of parabola:

(y-k)²=4p(x-h), with:

a) vertex = (h,k)

b) focus = (h+p, k)

c) directrix = (x=h-p)


Since this parabola has a vertex at (0,0) that means h=k=0

Hence the equation becomes: y²=4px, let's calculate p:
focus is given (-9,0) Remember h+p = -9 & since h=0, then p= -9
===> y²= - 36x
8 0
4 years ago
Other questions:
  • Cathy is paid at a rate of $7 20 per hour for a basic hour-week of 70 hours. She is paid time-and-a-half for over-time during th
    9·2 answers
  • Find the surface area of a figure
    7·1 answer
  • The vertical cross-section of a solid is shown below has 10 in every side angle
    11·1 answer
  • Which of the following is the solution set of the equation
    15·1 answer
  • PLEASE HELP!!!!!
    12·1 answer
  • What are some factors of 12
    13·2 answers
  • Which is a graph of y=3x−1?
    9·1 answer
  • The sum of twice a number and three is 21. find the number
    10·1 answer
  • Ruth is making a necklace for a friend. She has 3 different types of clasps, 2 different chains, and 5 different charms. If she
    13·1 answer
  • Solve for m<br> y - y₁ = m (x - x₁)
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!