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3 years ago

1. Which of the following is not a linear equation in one variable?

Mathematics

1 answer:

Lorico [155]3 years ago

5 0

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Which of the following is not a linear equation in one variable?

a) 33

b) 33(x+y)

c) 33x

d) 33y

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Option <em><u>b) 33 (x + y)</u></em> is not a linear equation in 1 variable.
Here, we can see that there are 2 variables used ⇨ x & y. Hence, even though it's a linear equation, it's not in 1 variable.
All the other options are in 1 variable or don't have a variable at all.

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A convenience store requires that Ayumi spend $4 or more if she wants to pay using a debit card. Donuts cost $0.80 each. A

IgorLugansk [536]

Answer

1.20+0.80d ≥ 4.00 is the equation. If you are trying to solve for the minimum of donuts she needs to buy so it is over $4.00, then it is 4

Step-by-step explanation:

So in the problem we know she already has bought one bottle of orange juice and needs to buy a certain amount of donuts but we know they are each 0.80 so that will become 0.80d. The 1.20 + 0.80d have to be greater than or equal to 4.00 so she can pay with the debit card and that is why we put the ≥ symbol.

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3 years ago

Read 2 more answers

There are two types of farming tractors on the market, the FT250 and the FT500. The only difference between the two is that the

irina [24]

Answer:

The statistical value farmers place on avoiding a tractor accident is $200,000.

The statistical value farmers place on avoiding a tractor fatal accident is $15,000,000.

Step-by-step explanation:

We have two tractors, with different probabilities of non-fatal and fatal accidents, and also different prices.

We will use this price difference to estimate how it is valued a non-fatal and fatal accident.

The difference in prices is:

$\Delta P=125,000-137,000=-12,000$

The expected non-fatal accidents for each tractor is

$FT500\rightarrow 1/10=0.1\\\\FT250 \rightarrow 1/25=0.04$

The difference in expected non-fatal accidents is:

$\Delta NFA = 0.10-0.04=0.06$

For a 6% more chance of having an accident, the farmers discounts 12,000 for the price of the less safe of the tractors.

Then, we can calculate the statistical value farmes place on avoiding a tractor accident as:

$V_{NFA}=\frac{-\Delta P}{\Delta NFA} =\frac{12,000}{0.06} =200,000$

The expected fatal accidents for each tractor is

$FT500\rightarrow 1/1,000=0.0010\\\\FT250 \rightarrow 1/5,000=0.0002$

The difference in expected fatal accidents is:

$\Delta NFA = 0.0010-0.0002=0.0008$

For a 0.08% more chance of having an fatal accident, the farmers discounts 12,000 for the price of the less safe of the tractors.

Then, we can calculate the statistical value farmes place on avoiding a tractor accident as:

$V_{FA}=\frac{-\Delta P}{\Delta FA} =\frac{12,000}{0.0008} =15,000,000$

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3 years ago

Help... thank you! Please!

S_A_V [24]

Answer:

4. 8

5. 0

6. C

7. ODE

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4 years ago

1. The following diagram shows a slide at a park. a. Find the vertical distance from the ground to the top of the slide. b. Find

xenn [34]

The area of the space under the slide is 2.10 square meters

<h3>The vertical distance</h3>

The diagram in the question is added as an attachment

The vertical distance is represented by h.

So, we have:

sin(70) = h/2

Solve for h

h = 2 * sin(70)

Evaluate

h = 1.88 m

Hence, the vertical distance is 1.88 m

<h3>The length of the slide</h3>

This is calculated using

sin(40) = h/Slide

This gives

sin(40) = 1.88/Slide

Solve for Slide

Slide = 1.88/sin(40)

Evaluate

Slide = 2.92

Hence, the length of the slide is 2.92 m

<h3>The area of the space under the slide</h3>

This is calculated using:

A = 0.5 * h * slide * sin(∅)

Where

∅ = 90 - 40 = 50

So, we have:

A = 0.5 * 1.88 * 2.92 * sin(50)

Evaluate

A = 2.10

Hence, the area of the space under the slide is 2.10 square meters