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dem82 [27]
2 years ago
10

A regular deck of cards has 52 cards. assuming that you do not replace the card you had drawn before the next draw, what is the

probability of drawing three aces in a row?
SAT
1 answer:
Rudiy272 years ago
7 0

The probability of drawing three aces in a row is the likelihood of drawing three aces

The probability of drawing three aces in a row is 0.000181

<h3>How to determine the probability?</h3>

In a standard deck of 52 cards, there are 4 aces.

Given that the selection is without replacement; then we have the following selections:

  • First: 4 aces in 52 cards
  • Second: 3 aces in 51 cards
  • Third: 2 aces in 50 cards

The probability is then calculated as;

P = \frac{4}{52} * \frac{3}{51} * \frac{2}{50}

Evaluate the products

P = 0.00018099547

Approximate

P = 0.000181

Hence, the probability of drawing three aces in a row is 0.000181

Read more about probability at:

brainly.com/question/251701

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The speaker’s series of exclamations in lines 31-33 (""sweet. . . Pan"") interrupt the pace of the narrative in order to.
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The reason for the speakers interruption of the narrative was to; dramatize the overwhelming beauty that is revealed as Pan begins to play

<h3>What is the aim of the speaker?</h3>

This question is taken from a poem that shows a dramatic retelling of a mythological story that resonates with the speaker's experience.

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Once you have your heap structure created, next you must use it as a backing structure to a priority queue. Develop a PriorityQu
saveliy_v [14]

Using the knowledge in computational language in python it is possible to write a code that Develop a PriorityQueue data structure in a file.

<h3>Writting the code in python:</h3>

<em>import sys</em>

<em>class Node:</em>

<em>def __init__(self,key):</em>

<em>self.left = None</em>

<em>self.right = None</em>

<em>self.val = key</em>

<em>self.parent = None</em>

<em>class MinHeap:</em>

<em>def __init__(self, maxsize):</em>

<em>self.maxsize = maxsize</em>

<em>self.size = 0</em>

<em>self.Heap = Node(-1 * sys.maxsize )</em>

<em>self.FRONT = self.Heap</em>

<em># A utility function to do inorder tree traversal</em>

<em>def isLeaf(self, node):</em>

<em>if node.left == None and node.right == Node:</em>

<em>return True</em>

<em>return False</em>

<em># Function to swap two nodes of the heap</em>

<em>def swap(self, node1, node2):</em>

<em>node1.data, node2.data = node2.data, node1.data</em>

<em># Function to heapify the node at pos</em>

<em>def minHeapify(self, node):</em>

<em># If the node is a non-leaf node and greater</em>

<em># than any of its child</em>

<em>if not self.isLeaf(node):</em>

<em>if (node.data > node.left.data or</em>

<em>node.data > node.right.data):</em>

<em># Swap with the left child and heapify</em>

<em># the left child</em>

<em>if node.left.data < node.right.data:</em>

<em>self.swap(node, node.left)</em>

<em>self.minHeapify(node.left)</em>

<em># Swap with the right child and heapify</em>

<em># the right child</em>

<em>else:</em>

<em>self.swap(node, node.right)</em>

<em>self.minHeapify(node.right)</em>

<em># Function to insert a node into the heap</em>

<em>def insert(self, element):</em>

<em>if self.size >= self.maxsize :</em>

<em>return</em>

<em>self.size+= 1</em>

<em>self.bst_insert(FRONT, element)</em>

<em>current = FRONT</em>

<em>while current.parent != None and current.data < current.parent.data:</em>

<em>self.swap(current, current.parent)</em>

<em>current = current.parent</em>

<em># Function to print the contents of the heap</em>

<em>def Print(self):</em>

<em>self.inorder()</em>

<em># Function to build the min heap using</em>

<em># the minHeapify function</em>

<em>def inorder(self, root):</em>

<em>if root:</em>

<em>inorder(root.left)</em>

<em>print(root.val)</em>

<em>inorder(root.right)</em>

<em>def bst_insert(self, root, node):</em>

<em>if root is None:</em>

<em>root = node</em>

<em>else:</em>

<em>root.next = node</em>

<em>self.FRONT = node</em>

<em># Driver Code</em>

<em>if __name__ == "__main__":</em>

<em>r = Node(50)</em>

<em>bst_insert(r,Node(30))</em>

<em>bst_insert(r,Node(20))</em>

<em>bst_insert(r,Node(40))</em>

<em>bst_insert(r,Node(70))</em>

<em>bst_insert(r,Node(60))</em>

<em>bst_insert(r,Node(80))</em>

<em># Print inoder traversal of the BST</em>

<em>inorder(r)</em>

<em>print('The minHeap is ')</em>

<em>minHeap = MinHeap(15)</em>

<em>minHeap.insert(5)</em>

<em>minHeap.insert(3)</em>

<em>minHeap.insert(17)</em>

<em>minHeap.insert(10)</em>

<em>minHeap.insert(84)</em>

<em>minHeap.insert(19)</em>

<em>minHeap.insert(6)</em>

<em>minHeap.insert(22)</em>

<em>minHeap.insert(9)</em>

<em>minHeap.minHeap()</em>

<em>minHeap.Print()</em>

<em>print("The Min val is " + str(minHeap.remove()))</em>

See more about python at brainly.com/question/13437928

#SPJ1

6 0
2 years ago
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