Solve 58 - 10x< 20 + 9x. - O A. x2 O B. Xs2 O c. xs-2 O D. x2-2
1 answer:
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The graph is continuous.A viable solution is (10, 50) at the function t = c + 40.
The complete question is given below:-
The temperature, t, in degrees Fahrenheit, can be found by counting the number of cricket chirps, c, heard in 14 seconds and then adding 40. The equation t = c + 40 models the relationship between the temperature and the number of cricket chirps. What is true about the graph that represents this real-world scenario? Check all that apply.
<h3>What is a graph?</h3>A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.
The graph is continuous.
A viable solution is (10, 50).
t = c + 40
The given equation is
t = c + 40
This equation models the relationship between the temperature and the number of cricket chirps.
Where is the temperature in degrees Fahrenheit and is the number of cricket chirps heard in 14 seconds?
According to the problem, the temperature can be found by counting the number of cricket chirps heard in 14 seconds and then adding 40.
Now, the choices to this question are
The graph is continuous.
All values of t must be positive.
A viable solution is (–2, 38).
A viable solution is (0.5, 40.5).
A viable solution is (10, 50).
The graph of the given equation is attached, it shows the linear relationship between both variables.
Notice that the graph is continuous, it doesn't have any restriction, nor "emptiness" at certain values.
Observe that the remaining choices are all solutions to the equation, but not all of them are viable because the number of cricket chirps must be positive and integer because we can't hear the sound of 0.5 cricket.
Therefore, the last choice is viable (10, 50).
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Answer:
57 units^2
Step-by-step explanation:
First find the area of the triangle on the left
ABC
It has a base AC which is 9 units and a height of 3 units
A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5
Then find the area of the triangle on the right
DE
It has a base AC which is 6 units and a height of 1 units
A = 1/2 bh = 1/2 ( 6) *1 = 3
Then find the area of the triangle on the top
It has a base AC which is 3 units and a height of 3 units
A = 1/2 bh = 1/2 ( 3) *3 = 9/2 = 4.5
Then find the area of the rectangular region
A = lw = 6*6 = 36
Add them together
13.5+3+4.5+36 =57 units^2
