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iragen [17]
3 years ago
12

Mr Yup sold her old car worth RM56 160 and incurred a loss of 28%. What was the original price of the car

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0
Ok so after a loss of 28% she sold for 160

100-28=72

therefor
160=72%
find 100%
160:72=x:100
160/72=x/100
20/9=x/100
mutlply both sides by 900
2000=9x
divide boht sides by 9
222.2222222222=x
about $222.22

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56 in scientific notation is 5.6 × 102. True or false?
Rama09 [41]
56 = 0.56 × 10²

so the answer is false :)

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3 0
3 years ago
Tammy wants to get change for $.30. The only coins she can get are quarters, nickels and dimes. How many different ways can she
Dmitry_Shevchenko [17]
1. One quater and one nicle   2. Three Dimes   3. 6 nickels 4. One dime and four nickles 5. two nickles and two dimes  i think
8 0
4 years ago
BRAINIEST TO WHOEVER RIGHT plz
Aleks04 [339]

Answer:

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3 0
3 years ago
State University uses thousands of fluorescent light bulbs each year. The brand of bulb it currently uses has a mean life of 600
Ipatiy [6.2K]

Answer:

The test statistic is t = 2.5.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

Step-by-step explanation:

Mean life of 600 hours. Test if it is more.

At the null hypothesis, we test if the mean is of 600 hours, that is:

H_0: \mu = 600

At the alternative hypothesis, we test if the mean is of more than 600 hours, that is:

H_1: \mu > 600

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

600 is tested at the null hypothesis:

This means that \mu = 600

Suppose 100 bulbs were tested and found to have a mean of 625 hours with a standard deviation of 100.

This means that n = 100, X = 625, s = 100.

Value of the test-statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{625 - 600}{\frac{100}{\sqrt{100}}}

t = 2.5

The test statistic is t = 2.5.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 625 hours, which is a right-tailed test, with t = 2.5 and 100 - 1 = 99 degrees of freedom.

Using a t-distribution calculator, this p-value is of 0.007.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

4 0
3 years ago
If a &gt; b &gt; c &gt; d, then which is larger, a+c or b+d ? Can we tell from a &gt; b &gt; c &gt; d which of a+d and b+c is la
victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

<u>1. Which is larger, a+c or b+d?</u>

Let a, b, c, and d be any numbers such that a > b > c > d.

Specifically, note that a > b, and subtracting b from both sides of the inequality, observe that a-b > 0.

Similarly, c > d, and subtracting d from both sides of the inequality, observe that c-d > 0.

From this, <u>add "a-b"</u> (a positive number, as proven above) to both sides of the inequality.

(a-b)+(c-d) > (a-b)+0

Addition by zero (<u>the additive identity</u>) doesn't change anything, so the right side remains "a-b"...

(a-b)+(c-d) > a-b

... and <u>"a-b" is positive</u>...

(a-b)+(c-d) > a-b > 0

... so, by the <u>transitive property</u> of inequality...

(a-b)+(c-d) > 0

Recall that <u>subtraction is addition by a negative</u> number...
a+(-b)+c+(-d) > 0

...and that <u>addition is associative and commutative</u>, so things can be added in any order, so the middle two terms on the left side can be rearranged...

a+c+(-b)+(-d) > 0

<u>Adding b + d</u> to both sides of the inequality

(a+c+(-b)+(-d))+(b+d) > 0+(b+d)

... and <u>simplifying</u>

a+c > b+d

So, a+c is larger than b+d.

<u>2. Which is larger, a+d or b+c?</u>

Consider the following two examples:

<u>Example 1</u>

Suppose a=10; b=3; c=2; d=1.

Note that a > b > c > d (10 > 3 > 2 > 1) and, also observe that a+d=(10)+(1)=11, and b+c=(3)+(2)=5, so a+d is larger than b+c.

<u>Example 2</u>

However, suppose a=10; b=9; c=8; d=1.

Note that a > b > c > d (10 > 9 > 8 > 1) but that a+d=(10)+(1)=11, and b+c=(9)+(8)=17, so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller.  Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0
2 years ago
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