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lbvjy [14]
2 years ago
13

A small container is shaped like this hexagonal prism. The prism has a base area of 7.85 cm².

Mathematics
2 answers:
Zielflug [23.3K]2 years ago
8 0
31.4 have a great day :)
Aliun [14]2 years ago
4 0

Answer:

31.4

Step-by-step explanation:

I reaally hope this helps you

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A civil engineer is designing a public parking lot for the new town hall. The number of cars in each row should be six less than
Alexandra [31]
The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars

Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:

y = x - 6             (1)

The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:

xy = 112           (2)

Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.

Using the value of y from equation 1 to 2, we get:

x(x - 6) = 112       (3)

This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.
6 0
2 years ago
12.589 en numeros romanos
inysia [295]
XII should be your answer.
8 0
3 years ago
Please help i have such a low GPA and i have to get it up so i can get into high school 100 points
enyata [817]

Answer:

<em>Well, The volume of the sink shaped like a half sphere is [2000/3] π in^2.</em>

<em />

<em>a) The volume of a cylinder is the area of the base * height</em>

<em />

<em>For this part the cup has a diameter, d, of 4 in and height, h, of 8 in.</em>

<em />

<em>The area of the base is π (d/2)^2 = π (2 in)^2  =  4π in^2.</em>

<em />

<em>The volume of the cuo is 4π in^2 * 8 in = 32π in^3.</em>

<em />

<em>Then the number of cups to take the volume of [2000 / 3] π in^2 is:</em>

<em />

<em>[2000 / 3]π / [32π] = 20.83</em>

<em />

<em>Answer: 21 cups.</em>

<em />

<em>b) For this part the diameter of the cup is 8 in and the height is 8 in</em>

<em />

<em>Then the volume is π (4 in)^2 * 8 in = 128 ⇅ in^3</em>

<em />

<em>And the number of cups needed is [2000π/3] / (128π) = 5.2 </em>

<em />

<em>Answer: 5 cups. </em><em>Good Luck!</em>

<em>From ~Itsbrazts~.</em>

<em />

8 0
2 years ago
Read 2 more answers
When we test Upper H 0​: muequals0 against Upper H Subscript a​: mugreater than​0, we get a​ P-value of 0.03. a. What would the
Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

(c) The null hypothesis will not be rejected. The error is type II error.

Step-by-step explanation:

The hypothesis provided is:

H_{0}: \mu = 0\\ H_{a} : \mu > 0

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

p-value = 0.03 < \alpha  = 0.10

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in​ (a) is an​ error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

p-value = 0.03 > \alpha  = 0.01

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

3 0
3 years ago
Please help me I will give a brainly!!!!
nydimaria [60]

Answer:

Yes

Step-by-step explanation:

1 : The athlete's hands push the medicine ball forward. The medicine ball pushes the athlete's hands backward.

2: Friction

3: The first pair of action-reaction force pairs is: foot A pushes ball B to the right; and ball B pushes foot A to the left. The second pair of action-reaction force pairs is: foot C pushes ball B to the left; and ball B pushes foot C to the right

7 0
1 year ago
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