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2 years ago

PLEASE HELP PLEASE HELP I WILL GIVE BRAINLIEST

Mathematics

1 answer:

aliya0001 [1]2 years ago

5 0

Answer:

Jenna's line would be: C Line L

Step-by-step explanation:

The x coordinates and y coordinates from Jenna's table matches up with the points on Line L. Hope this helped! :)

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Work out the angle of elevation from the

insens350 [35]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:Angle \:\: of \:\: elevation= 30°$

____________________________________

$\large \tt Solution \: :$

Let the angle of elevation be " x "

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{9 \sqrt{3} }{18}$

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{ \sqrt{3} }{2}$

$\qquad \tt \rightarrow \: x = \cos {}^{ - 1} \bigg( \cfrac{ \sqrt{3} }{2} \bigg )$

$\qquad \tt \rightarrow \: x = 30 \degree \: \: or \: \: \cfrac{ \pi}{6} \: \: rad$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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2 years ago

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If a truck averages 17 miles to the gallon, how many pounds of carbon dioxide are emitted into the atmosphere when the truck tra

dimulka [17.4K]

The answer might be 13.88

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3 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

To find:

The probability that a randomly selected students plays both = ?

Solution:

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0$

So, 0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

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3 years ago

For question 3, use the Pythagorean Theorem.

Juliette [100K]

Step-by-step explanation:

can't really use the Pythagorean because you don't know this is a right triangle.

use the fact that they are similar

3/6 = x/12 where x is FE

cross multiply

6x = 36 therefore FE = 6

then 6/12 = y/9 where y is FD

cross multiply

12y = 54 = 54/12 therefore FD = 4.5

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3 years ago

A bottle of jam contains 10 pints of jam. How many 1/3 pint servings can you get out of one bottle?

Sergeeva-Olga [200]

You can get 30 servings of jam out of the bottle.

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