5) 2 3/35
6) 8 5/8
7) 9/40
8) 5 7/10
Hey!
To find out how much it is in cups, we must know how many cups 1 quart is equal to.
1 quart = 4 cups.
5 1/2 (or 5.5) quarts = 22 cups.
Let me show u one in detail.
First we have to find the common ratio. We do this by dividing the second term by the first term.
ur first problem...
12/3 = 4...so the common ratio is 4
now we use the formula
an = a1 * r^(n-1)
n = term u want to find = 15
a1 = first term = 3
r = common ratio = 4
now we sub
a15 = 3 * 4^(15 - 1)
a15 = 3 * 4^14
a15 = 3 * 268435456
a15 = 805,306,368 <== ur 15th term
thats all there is to it...and, of course, u can always look on the internet for a geometric sequence calculator...to check urself...lol
![\bf cos\left[tan^{-1}\left(\frac{12}{5} \right)+ tan^{-1}\left(\frac{-8}{15} \right) \right]\\ \left. \qquad \qquad \quad \right.\uparrow \qquad \qquad \qquad \uparrow \\ \left. \qquad \qquad \quad \right.\alpha \qquad \qquad \qquad \beta \\\\\\ \textit{that simply means }tan(\alpha)=\cfrac{12}{5}\qquad and\qquad tan(\beta)=\cfrac{-8}{5} \\\\\\ \textit{so, we're really looking for }cos(\alpha+\beta)](https://tex.z-dn.net/?f=%5Cbf%20cos%5Cleft%5Btan%5E%7B-1%7D%5Cleft%28%5Cfrac%7B12%7D%7B5%7D%20%20%5Cright%29%2B%20tan%5E%7B-1%7D%5Cleft%28%5Cfrac%7B-8%7D%7B15%7D%20%20%5Cright%29%20%5Cright%5D%5C%5C%0A%5Cleft.%20%5Cqquad%20%20%5Cqquad%20%20%5Cquad%20%20%20%5Cright.%5Cuparrow%20%5Cqquad%20%5Cqquad%20%20%5Cqquad%20%20%5Cuparrow%20%5C%5C%0A%5Cleft.%20%5Cqquad%20%20%5Cqquad%20%20%5Cquad%20%20%20%5Cright.%5Calpha%20%5Cqquad%20%5Cqquad%20%20%5Cqquad%20%20%5Cbeta%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bthat%20simply%20means%20%7Dtan%28%5Calpha%29%3D%5Ccfrac%7B12%7D%7B5%7D%5Cqquad%20and%5Cqquad%20tan%28%5Cbeta%29%3D%5Ccfrac%7B-8%7D%7B5%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bso%2C%20we%27re%20really%20looking%20for%20%7Dcos%28%5Calpha%2B%5Cbeta%29)
now.. hmmm -8/15 is rather ambiguous, since the negative sign is in front of the rational, and either 8 or 15 can be negative, now, we happen to choose the 8 to get the minus, but it could have been 8/-15
ok, well hmm so, the issue boils down to
now, let's take a peek at the second angle, angle β
now, with that in mind, let's use the angle sum identity for cosine
The year of the empire fell = 1610.
We are given x as a variable that represents the year after the given year 1610.
We need to setup an inequality for this situation.
Please note: The year after the year number 1610 will have a number that greater than 1610.
Let us make a statement for inequality to be written.
"The year after the 1610 is greater than 1610".
The year after the 1610 is x and gerater than symbol is >.
So, we can setup an inequality as:
x > 1610 : Read as x is greater than 1610.
